Ask question

Ask question

All categories

3 years ago

5

Whats .275 as a mixed number

2 answers:

iris [78.8K]3 years ago

6 0

So what i would do would be put 275/1000 then keep simplifying so 55/200, then 11/40 since 11/40 cant be reduced 11/40 would be your answer

:)

Monica [59]3 years ago

5 0

.275 would be equal to 11/40... There is no mixed number as an answer to this question because it is less than zero, and can not have an integer.along side the proper fraction.

If you mean 275% the answer would be 2 3/4

You might be interested in

Can someone help me pls

DaniilM [7]

Answer:

Step-by-step explanation:

Look at the photo

5 0

3 years ago

I Need help! If you help me you'll get 10 points!!

natka813 [3]

To solve this problem you must apply the proccedure shown below:

1. You have that the number of innings are expressed as a mixed number in the exercise:

$102^{\frac{2}{3} }$

2. If you want to write it as a decimal, you can convert the fraction as a decimal by dividing the numerator by the denominator and then, you must add this to the whole number part:

$102+\frac{2}{3}=102+0.67=102.67$

The answer is: 102.67

7 0

3 years ago

Write equation for horizontal line and vertical lines passing through the point of 0 and 7

Alborosie

Answer:

Step-by-step explanation:

for horizontal line slope m=0

eq. of horizontal line at (0,7) with slope 0 is

y-7=0(x-0)

y-7=0

or

y=7

slope of vertical line=∝

eq of vertical line through (0,7) is

y-7=∝(x-0)

or

x-0=0(y-7)

x-0=0

or

x=0

6 0

2 years ago

8. Solve the following proportion (1 point)

Arturiano [62]

Answer:

97.5

Step-by-step explanation:

Cross multiply

2 * x = 2x

15 * 13 = 195

2x = 195

2x/2 = 195/2

x = 97.5

[RevyBreeze]

6 0

2 years ago

Read 2 more answers

Find the volume of the solid in the first octant bounded by the coordinate planes, the cylinder X^2+Y^2=4 and the plane X+Z=4.

stira [4]

Answer:

$4\pi- \frac{8}{3}$

Step-by-step explanation:

The solid that you described is shown in the image of below. To compute the volume we use triple integrals. Observe that

$0\leq x\leq 2$

$0\leq y \leq \sqrt{4-x^2}$

$0\leq z \leq 4-x$

So, the volumen of the solid is given by

$\int_{0}^{2}\int_{0}^{\sqrt{4-x^2}}\int_{0}^{4-x}1\, dzdydx=\int_{0}^{2}\int_{0}^{\sqrt{4-x^2}}4-x\, dydx=\int_{0}^{2}(4-x)\sqrt{4-x^2}\,dx$

This last integral equals $4\pi -\frac{8}{3}$

5 0

3 years ago