Answer:
We know that in a triangle, if two angles have equal measures, then the sides opposite to them are equal in length. Thus, the length of side AB is 6 units
Answer:
10:12
15:18
20:24
25:30
Step-by-step explanation:
you could just multiply 5 and 6 by the same number so you would get ratios that are equal to each other so for example for 10:12 5 and 6 is getting multiplied by 2
Answer:
9
Step-by-step explanation: did it
Answer:
m∠CEB is 55°
Step-by-step explanation:
Since ∠ADE = 55°, and ∠ADE is half of ∠ADC because ED bisects ∠ADC. Bisect means to cut in half.
∠ADC = 110° because it is double of ∠ADE.
Since AB║CD and AD║BC, the two sets of parallel lines means this shape is a parallelogram. In parallelograms, <u>opposite angles have equal measures</u>.
∠ADC = ∠CBE = 110°
All quadrilaterals have a sum of angles 360°. Since ∠DCB = ∠BAD and we know two of these other angles are each 110°:
360° - 2(110°) = 2(∠DCB)
∠DCB = 140°/2
∠DCB = ∠BAD = 70°
∠DCB was bisected by EC, which makes each divided part half.
∠DCE = ∠BCE = (1/2)(∠DCB)
∠DCE = ∠BCE = (1/2)(70°)
∠DCE = ∠BCE = 35°
All triangles' angles sum to 180°.
In ΔBCE, ∠BCE = 35° and ∠CBE = 110°.
∠CEB = 180° - (∠BCE + ∠CBE)
∠CEB = 180° - (35° + 110°)
∠CEB = 55°
Therefore m∠CEB is 55°.
ANSWER
the factor <em>will </em>
<em>1</em><em>1</em><em> </em><em>is </em><em>common</em><em> </em><em>in </em><em>both </em><em>the </em><em>given </em><em>term</em>
<em>so,</em><em> </em><em>when </em><em>we </em><em>take </em><em>1</em><em>1</em><em> </em><em>from </em><em>both </em><em>term </em>
<em>it </em><em>will </em><em>left </em><em>with </em><em> </em>
<em>1</em><em>1</em><em>(</em><em> </em><em>2</em><em>+</em><em>1</em><em>)</em><em> </em>
<em>this </em><em>is </em><em>the </em><em>final </em><em>answer</em><em> </em>
<em>hope </em><em>it </em><em>helps </em><em>and </em><em>u </em><em>have </em><em>a </em><em>great</em><em> </em><em><u>day</u></em>