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Semenov [28]
3 years ago
11

Angela and Jose saved files to a USB drive as well as on their computers' hard drive. A Angela and Jose saved files to a USB dri

ve as well as on their computers' hard drive. Angela says when she makes changes to a file on the USB drive, the same file on her computer will update. Jose says that the files on the USB drive won't be in sync with the files on his computer. Who is correct? A. Neither is correct. B. Both are correct. C. Only Angela is correct. D. Only Jose is correct.ngela says when she makes changes to a file on the USB drive, the same file on her computer will update. Jose says that the files on the USB drive won't be in sync with the files on his computer. Who is correct? A. Neither is correct. B. Both are correct. C. Only Angela is correct. D. Only Jose is corre
Computers and Technology
1 answer:
zvonat [6]3 years ago
4 0
The answer is:
D. Only Jose is correct


When the two files are saved in different locations they are new and different files, not the same. If you change one it wont change the other.
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Purpose of this project is to increase your understanding of data, address, memory contents, and strings. You will be expected t
STALIN [3.7K]

Answer:

See explaination for the details

Explanation:

#Starting point for code/programm

main:

la $a0,newLine #Print a new line

li $v0,4

syscall

# Find the number of occurence of a string in the given sentence

la $a0,prompt1 # Prompt the user to enter the first string.

li $v0,4

syscall

li $v0, 8 # Service 8 = read input string

la $a0, fword

li $a1, 9

syscall

la $a0,prompt2 # Prompt the user to enter the second string.

li $v0,4

syscall

li $v0, 8 # Service 8 = read input string

la $a0, sword

li $a1, 9

syscall

# process first word

li $t4,0 # Intialize the couter to 0

la $t0,sstatement # Store the statement into $t0

nstart1: la $t1,fword # Store the search word into $t1

loop1: # loop1 finds the number of occurences

# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

lb $t3,($t1) # Load the starting address of input word

# into $t3

beq $t3,'\n',inc_counter1

beqz $t3,inc_counter1 # If $t3 is null , exit loop and print output

beqz $t2,print_output1 # If $t2 is null , exit loop and print output

move $a0,$t2 # Convert $t2 to lower, if it is upper case

jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char1 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop1 # go to starting of the loop

next_char1:

la $t5,fword

bne $t5,$t1,nstart1

la $t1,fword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop1 # go to starting of the loop

inc_counter1:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,fword # Store input word into $t1

j loop1 # go to starting of the loop

print_output1:

la $t0,fword

L1:

lb $a0,($t0)

beq $a0,'\n',exL1

jal convert2upper

move $a0,$v0

li $v0,11

syscall

addiu $t0,$t0,1

j L1

exL1:

la $a0,colon

li $v0,4

syscall

la $a0, dash

li $v0, 4

syscall

move $a0,$t4

li $v0,1

syscall # print new line

la $a0,newLine

li $v0,4

syscall

# process second word

li $t4,0 # Intialize the couter to 0

la $t0,sstatement # Store the statement into $t0

nstart2: la $t1,sword # Store the search word into $t1

loop2: # loop1 finds the number of occurences

# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

lb $t3,($t1) # Load the starting address of input word

# into $t3

beq $t3,'\n',inc_counter2

beqz $t3,inc_counter2 # If $t3 is null , exit loop and print output

beqz $t2,print_output2 # If $t2 is null , exit loop and print output

move $a0,$t2 # Convert $t2 to lower, if it is upper case

jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char2 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop2 # go to starting of the loop

next_char2:

la $t5,sword

bne $t5,$t1,nstart2

la $t1,sword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop2 # go to starting of the loop

inc_counter2:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,sword # Store input word into $t1

j loop2 # go to starting of the loop

print_output2:

la $t0,sword

L2:

lb $a0,($t0)

beq $a0,'\n',exL2

jal convert2upper

move $a0,$v0

li $v0,11

syscall

addiu $t0,$t0,1

j L2

exL2:

la $a0,colon

li $v0,4

syscall

la $a0, dash2

li $v0, 4

syscall

move $a0,$t4

li $v0,1

syscall

exit:

# Otherwise, end the program

li $v0, 10 # Service 10 = exit or end program

syscall

############################ subroutine - convert2lower #################################

convert2lower: # Converts a character(stored in $a0) to

# its lower case, if it is upper case

# and store the result(lower case) in $v0

move $v0,$a0

blt $a0,'A',return

bgt $a0,'Z',return

subi $v0,$a0,-32

return: jr $ra # Return the converted(lower case) character

############################## subroutine - convert2upper ##################################

convert2upper: # Converts a character(stored in $a0) to

# its upper case, if it is lower case

# and store the result(upper case) in $v0

move $v0,$a0

blt $a0,'a',return2

bgt $a0,'z',return2

addiu $v0,$a0,-32

return2: jr $ra # Return the converted(lower case) character

4 0
3 years ago
Halp Computer Science
AleksandrR [38]

1st one: is memory

2nd one: is 8

8 0
3 years ago
Read 2 more answers
Which of the following is lost when the computer is turned off?
Sergeeva-Olga [200]

Answer:

Memory (RAM) is lost when computer is turned off.

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3 years ago
How many dimples are on the titleist pro v1 golf ball?
ICE Princess25 [194]
Hey and thanks for giving me the chance to serve you
__________________________________________________________ 

There are 392 dimples on a Pro V 1,
Hope this helped.

Have a good day.
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3 years ago
JavaScript uses which property to change the current content of HTML elements?
solong [7]

Answer:

innerHTML

Explanation:

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