Well 1st you power the computer on then u login with ur username and password the boss should give u, then go to the left corner click it search for microsoft word and click new document
Answer:
A for loop can be used to make something repeat as many times as you program it to, but a while loop only stops when you complete the task, or a certain condition is met. So, if you program a for loop to fill a bucket six times it will fill the bucket six times.
Answer:
Check the explanation
Explanation:
Assuming Cust_code is unique for every customer.
Query :
SELECT * FROM CUSTOMER WHERE CUST_STATE= "AL" GROUP BY CUST_CODE HAVING LARGEST INVOICE = MAX(LARGEST INVOICE) OR (LARGEST INVOICE =0 and INV_DATE IS NULL);
Answer:
Warning signs tell you can or can't do, and what you must do?
Answer:
You can simplify the problem down by recognizing that you just need to keep track of the integers you've seen in array that your given. You also need to account for edge cases for when the array is empty or the value you get would be greater than your max allowed value. Finally, you need to ensure O(n) complexity, you can't keep looping for every value you come across. This is where the boolean array comes in handy. See below -
public static int solution(int[] A)
{
int min = 1;
int max = 100000;
boolean[] vals = new boolean[max+1];
if(A.length == 0)
return min;
//mark the vals array with the integers we have seen in the A[]
for(int i = 0; i < A.length; i++)
{
if(A[i] < max + 1)
vals[A[i]] = true;
}
//start at our min val and loop until we come across a value we have not seen in A[]
for (int i = 1; i < max; i++)
{
if(vals[i] && min == i)
min++;
else if(!vals[i])
break;
}
if(min > max)
return max;
return min;
}
