Answer:
1. Processor communication -- this involves the following tasks:
<em>a. exchange of data between processor and I/O module</em>
<em>b. command decoding - I/O module accepts commands sent from the processor. E.g., the I/O module for a disk drive may accept the following commands from the processor: READ SECTOR, WRITE SECTOR, SEEK track, etc. </em>
<em>c. status reporting – The device must be able to report its status to the processor, e.g., disk drive busy, ready etc. Status reporting may also involve reporting various errors. </em>
<em>d. Address recognition – Each I/O device has a unique address and the I/O module must recognize this address. </em>
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2. Device communication – The I/O module must be able to perform device communication such as status reporting.
3. Control & timing – The I/O module must be able to co-ordinate the flow of data between the internal resources (such as processor, memory) and external devices.
4. Data buffering – This is necessary as there is a speed mismatch between speed of data transfer between processor and memory and external devices. Data coming from the main memory are sent to an I/O module in a rapid burst. The data is buffered in the I/O module and then sent to the peripheral device at its rate.
5. Error detection – The I/O module must also be able to detect errors and report them to the processor. These errors may be mechanical errors (such as paper jam in a printer), or changes in the bit pattern of transmitted data. A common way of detecting such errors is by using parity bits.
Answer:
1. I express myself through the designing, development and analysis of software and hardware used to solve problems in a variety of business, scientific and social contexts.
2. support the development of general reasoning, problem-solving and communication skills.
3. Through avoiding in repetious tasks and simplifying such works.
Explanation:
The below code has been written in C language
void rotateright(int list[], int n)
{
int x = list[n-1]
int i;
for (i = n-1; i > 0; i--)
list[i] = list[i-1];
list[0] = x;
}
void rotateleft(int list[], int n)
{
int x = list[0]
int i;
for (i = 1; i < n-1 ; i++)
list[i] = list[i+1];
list[n-1] = x;
}
int main()
{
int list[] = {x1, x2, x3, ... x(n-1),xn}
int i;
int n = sizeof(list);
rotateright(list, n);
rotateleft(list, n);
return 0;
}
A speaker sometimes is not able to capture the intended details since it is affected by homophones.
A, B , and E sorry if I’m wrong
