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Virty [35]
3 years ago
9

UgH y’all help !!!! I’ll mark you brainliest ONLY if you get it RIGHT.

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
8 0
The answer is going to be   d. hope that helped
Natali5045456 [20]3 years ago
4 0
0,1 

all you have to do is graph it as it is.

You might be interested in
your uncle jim lives in england, where the current exchange rate is 1.64 US dollars for each British pound. Solve for the amount
Talja [164]

Based on the amount of your monthly bill, if you lived in England, your bill to the nearest hundredth is $185.82

<h3>How to find your bill in pound sterling?</h3>

You have a monthly bill of $304.72. If this was also your bill in England id you stayed there, it would need to be converted to pounds. The way to do this is by using the exchange rate.

If each British Pound is $1.64 U.S. Dollar, then the value of your monthly bill if you lived in England is:

= Monthly bill in dollars / Conversion or exchange rate

= 304.72 / 1.64

= $185.82

Find out more on the exchange rate at brainly.com/question/20332320

#SPJ1

7 0
1 year ago
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
gladu [14]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

5 0
2 years ago
Subtract 2xy-8 from 5x^2+3xy+12
JulijaS [17]

Answer:

5x^2 + xy + 20

Step-by-step explanation:

Begin with 5x^2+3xy+12,  Subtracting 2xy yields 5x^2 + xy + 12.  Next, subtracting -8 yields 5x^2 + xy + 12 - (-8), or   5x^2 + xy + 20

3 0
2 years ago
Fiona is trying to prove that a pair of expressions are equivalent by using substitution. Which pair of expressions has the same
fiasKO [112]

Missing Part of the Question

  • 3 (4 - y) -7 ; 5 + 3y
  • 9 + y + 4y - 2 - 3y; -2y + 7
  • 5 + y - 2 - 6y + y; 8y + 3
  • 2y + 7 + y - 2 + y; 4y + 5

Answer:

  • 2y + 7 + y - 2 + y; 4y + 5

Step-by-step explanation:

Given

y = 3

Required

Which pair of expression are equal

To get the pair of expression that are equal; we simply substitute 3 for y in each of the expressions

3 (4 - y) -7 and 5 + 3y

<em>Substitute 3 for y in 3 (4 - y) -7</em>

This gives 3(4 - 3) -7

= 3(1) - 7

= 3 - 7

= -4

<em>Then Substitute 3 for y in 5 + 3y</em>

This gives  5 + 3(3)

= 5 + 9

= 14

-4 and 14 are not equal

---------------------------------------------------------------------------------------

9 + y + 4y - 2 - 3y; -2y + 7

<em>Substitute 3 for y in </em>9 + y + 4y - 2 - 3y

This gives 9 + 3 + 4(3) - 2 - 3(3)

= 9 + 3 + 12 - 2 - 9

= 13

<em>Then Substitute 3 for y in -2y + 7</em>

This gives  -2(3) + 7

= -6 + 7

= 1

13 and 1 are not equal

---------------------------------------------------------------------------------------

5 + y - 2 - 6y + y; 8y + 3

<em>Substitute 3 for y in 5 + y - 2 - 6y + y</em>

This gives 5 + 3 - 2 - 6(3) + 3

= 5 + 3 - 2 - 18 + 3

= -9

<em>Then Substitute 3 for y in 8y + 3</em>

This gives  8(3) + 3

= 24 + 3

= 27

-9 and 27 are not equal

---------------------------------------------------------------------------------------

2y + 7 + y - 2 + y; 4y + 5

<em>Substitute 3 for y in 2y + 7 + y - 2 + y</em>

This gives 2(3) + 7 + 3 - 2 + 3

= 6 + 7 + 3 - 2 + 3

= 17

<em>Then Substitute 3 for y in 4y + 5</em>

This gives  4(3) + 5

= 12 + 5

= 17

17 and 17 are equal

Hence, Option D is correct

6 0
3 years ago
Given the Arithmetic series A 1 + A 2 + A 3 + A 4 A1+A2+A3+A4 14 + 18 + 22 + 26 + . . . + 86 What is the value of sum?
postnew [5]

Answer:

950

Step-by-step explanation:

The common difference is 4, so the general term can be written:

... an = 14 + 4(n -1)

The value of n for the last term is ...

... 86 = 14 + 4(n -1) . . . . . the computation for the last term, 86

... 72 = 4(n -1) . . . . . . . . . subtract 14

... 18 = n -1 . . . . . . . . . . . divide by 4

... 19 = n . . . . . . . . . . . . . add 1

Your series has 19 terms. The first term is 14 and the last is 86, so the average term is (14+86)/2 = 50. Since there are 19 terms, the sum of them is ...

... 19×50 = 950

7 0
3 years ago
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