Answer:
Step-by-step explanation:
A possible word problem for 3x+10 ≤75 could be
Mat has $75 dollars saved in his wallet and wants to use it for go carts. Knowing that the entrance to the park is $10, and each time around the go cart course is $3 what is the maximum times he can go around?
3x+10 ≤ 75, subtract 10 from both sides
3x ≤ 75-10, divide both sides by 3
x ≤ 65/3
or x ≤ 21.(6)
So it can go around 21 times the most.
Answer:
27/35 is the exact answer
7/10 is an estimate
Step-by-step explanation:
4/7+2/10
Simplify the fraction
4/7+1/5
The common denominator is 35
4/7*5/5 + 1/5 *7/7
20/35 + 7/35
27/35
To estimate
4/7 is close to 1/2
2/10 is close is 1/5
1/2 + 1/5 =
5/10 + 2/10 = 7/10
156 divided by 4 is 39 So each side is 39