Log7 (x+3) - log7 (x-3) = 1
log7 [(x+3) / (x-3)] = 1
raise both sides to power of 7
(x+3) / (x-3) = 7
7x – 21 = x + 3
6x = 24
x = 4
Answer:
ya you can take it both like integer and decimal
cause - the negative mark make it negative the . make it decimal
Step-by-step explanation:
this is the answer of the required questions
thank you
Answer:
Option 2: (1, 0) and (0, -5)
Step-by-step explanation:
Let's solve this system of equations using the elimination method.
Start by labelling the two equations.
5x -y= 5 -----(1)
5x² -y= 5 -----(2)
(2) -(1):
5x² -y -(5x -y)= 5 -5
Expand:
5x² -y -5x +y= 0
5x² -5x= 0
Factorise:
5x(x -1)= 0
5x= 0 or x -1= 0
x= 0 or x= 1
Now that we have found the x values, we can substitute them into either equations to solve for y.
Substitute into (1):
5(0) -y= 5 or 5(1) -y= 5
0 -y= 5 or -y= 5 -5
y= -5 or -y= 0
y= 0
Thus, the solutions are (0, -5) and (1, 0).
