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Nutka1998 [239]
2 years ago
15

George earned $3,200 for one month of work. He paid $640 in income tax for the month. What percent tax did he pay? (Ignore the p

ercent sign when gridding your answer.
Mathematics
1 answer:
lakkis [162]2 years ago
7 0

Answer:

He paid $640 out of his total $3,200 for the month.

As a fraction it is (640/3200) which equals (1/5)

We want it as a percentage so we multiply the fraction by 100.

1/5×100=20%

20% is the final answer.

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Andrej [43]
The answer is c. 1/9. 

If x = -2, y = -1, z = 3

then,    (-2(-1) -(-1)^2) / 3(3)

(2 - 1)/3(3)

1/9

3 0
3 years ago
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Phonics is an instructional method in which children are taught to connect sounds with letters or groups of letters. A sample of
natali 33 [55]

Answer:

98% confidence interval: (29.25,38.87)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 34.06

Sample size, n = 134

Sample standard deviation, s = 23.83

a) 98% confidence interval

\bar{x} \pm z_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

z_{critical}\text{ at}~\alpha_{0.02} = \pm 2.33  

34.06 \pm 2.33(\frac{23.83}{\sqrt{133}} ) = 34.06 \pm 4.81 = (29.25,38.87)

b)  If a 95% confidence interval were constructed with these data, confidence interval would be narrower as the confidence level is decreasing as compared to 98%

c)  If a sample of 150 students had been studied, the width of confidence interval will decrease as the sample size increases.

8 0
3 years ago
A car rental company charges $34 per day for a rented car and $0.50 for every mile driven. A second car rental company charges $
Ludmilka [50]

Answer:

B 2/3

Step-by-step explanation:

:)

5 0
3 years ago
Read 2 more answers
Prove that sin^4x + cos^4x= sinxcosx
yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

sin^4(x) + cos^4(x)

We can rewrite this as:

(sin^2(x))^2 + (cos^2(x))^2

Now we can add and subtract cos^2(x)*sin^2(x) to get:

(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)

We can complete squares to get:

(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2

and we know that:

cos^2(x) + sin^2(x) = 1

then:

1 - 2*sin(x)^2*cos(x)^2

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

1 - \frac{sin^2(2*x)}{2}

Then the simplification is:

cos^4(x) + sin^4(x)  = 1 - \frac{sin^2(2*x)}{2}

7 0
3 years ago
Which of the following rational functions is graphed below?​
vampirchik [111]

Answer:

The correct option is D.

i.e.

f\left(x\right)=\frac{1}{x\left(x+4\right)} is the correct option.

The correct graph is shown in attached figure.

Step-by-step explanation:

Considering the function

f\left(x\right)=\frac{1}{x\left(x+4\right)}

\mathrm{Domain\:of\:}\:\frac{1}{x\left(x+4\right)}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x

\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{None}

\mathrm{Extreme\:Points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{Maximum}\left(-2,\:-\frac{1}{4}\right)

So, the correct graph is shown in attached figure.

Therefore, the correct option is D.

i.e.

f\left(x\right)=\frac{1}{x\left(x+4\right)} is the correct option.

7 0
3 years ago
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