So based on your question about the line A and B meet and the four lines are congruent to each other. The graph doesnt show any measurements so there is no exact value to the length of X. But you must consider that the lines are proportional to each other so it means that they are congruent.
Answer:
Step-by-step explanation:
separate into squares
i separated it into three squares (rectangles);
9x5
3x2
3x2
find the area of the three then add, 45+6+6
Total Area = 57m^2
Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
Answer:![{ \left[\begin{array}{ccc}45.5\\\\\end{array}\right] }{}\\\\\end{array}\right] } ----](https://tex.z-dn.net/?f=%7B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D45.5%5C%5C%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7D%7B%7D%5C%5C%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7D%20----)
Step-by-step explanation: Hey, Basically we are going to arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers.
Hope this helps!
We know that:
time=distance/speed
if the tortoise speed is x m/min, then since 0.5 m/hr=1/120 m/min
18/x=23+18/(x+1/120)
solving for x we get:
x=0.08 m/min
speed of hare is:
(0.08+1/120)=0.088 m/min