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Komok [63]
3 years ago
14

If s = 24t + 3t2 - t3 what is the relative maximum

Mathematics
1 answer:
MAXImum [283]3 years ago
3 0
<span>v = 24 + 6t - 3t^2 is the correct answer</span>
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2x²-26x+84 (Factor COMPLETELY)
Nadya [2.5K]

\tt{} {2x}^{2}  - 26x + 84

\tt{}2 {(x}^{2}  - 13x + 42)

\tt{}2 {(x}^{2}  - 6x - 7x + 42)

\tt{}2( x \times (x - 6) - 7(x - 6))

\tt{}2(x - 6) \times (x - 7)

5 0
3 years ago
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
What set of transformations is performed on triangle RST to form triangle R’S’T’?
DanielleElmas [232]

Answer:

The last option is correct

Step-by-step explanation:

A translation of 2 units down takes S to the point (1, -1). Then a counterclockwise rotation  about the origin  takes S to the point  (-1, -1)  where we have S' .  

8 0
3 years ago
Read 2 more answers
What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Poin
egoroff_w [7]

Answer: \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

We need to find the coordinates of the point which is 3/4 of the way from A to B.

Let the required point be P.

AP:AB=3:4

AP:PB=AP:(AB-AP)=3:(4-1)=3:1

It means, point P divides segment AB in 3:1.

Section formula:  If a point divides a line segment in m:n, then

\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Using section formula, we get

P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)

P=\left(\dfrac{-9-5}{4},\dfrac{9-4}{4}\right)

P=\left(\dfrac{-14}{4},\dfrac{5}{4}\right)

P=\left(\dfrac{-7}{2},\dfrac{5}{4}\right)

Therefore, the required point is \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

6 0
3 years ago
Which statement most accurately explains why x^5/x^2 is equal to x^3?
Serggg [28]
\bf \cfrac{x^5}{x^2}\implies \cfrac{x^{3+2}}{x^2}\implies \cfrac{x^3\underline{x^2}}{\underline{x^2}}\implies x^3
8 0
3 years ago
Read 2 more answers
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