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Vlada [557]
3 years ago
9

Which is the best estimate for 6,193 ÷ 48 using compatible numbers.

Mathematics
2 answers:
Gala2k [10]3 years ago
8 0
It would be B. 120 you would usually round up but the closest one to 129.02083 is 130 and since there is no 130 it would be 120
Artist 52 [7]3 years ago
8 0

Answer:

The answer is B if you round that would be your closed option!

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Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
2&+5&(2x)^4(+3)^1\\
3&+10&(2x)^3(+3)^2\\
4&+10&(2x)^2(+3)^3\\
5&+5&(2x)^1(+3)^4\\
6&+1&(2x)^0(+3)^5
\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^4(-3y)^0\\
2&+4&(2x)^3(-3y)^1\\
3&+6&(2x)^2(-3y)^2\\
4&+4&(2x)^1(-3y)^3\\
5&+1&(2x)^0(-3y)^4
\end{array}


\bf (3a+4b)^8\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(3a)^8(+4b)^0\\
2&+8&(3a)^7(+4b)^1\\
3&+28&(3a)^6(+4b)^2\\
4&+56&(3a)^5(+4b)^3\\
5&+70&(3a)^4(+4b)^4\\
6&+56&(3a)^3(+4b)^5\\
7&+28&(3a)^2(+4b)^6\\
8&+8&(3a)^1(+4b)^7\\
9&+1&(3a)^0(+4b)^8
\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
-8(1 + 5b) – 2(86 – 1) = 50
kati45 [8]

Answer:

b = -57/10

Step-by-step explanation:

Let's first distribute everything out:

-8(1 + 5b) = -8 * 1 + (-8) * 5b = -8 - 40b

2(86 - 1) = 2 * 85 = 170

So, we have:

-8 - 40b - 170 = 50

-40b - 178 = 50

-40b = 50 + 178 = 228

b = -228/40 = -57/10

Thus, the answer is b = -57/10.

Hope this helps!

3 0
3 years ago
Please answer this correctly
musickatia [10]

There are 4 quarts in 1 gallon.

3 x 4 = 12

12 + 2 = 14 quarts

Hope this helps!! :)

6 0
3 years ago
What rule is this, please answer correctly, please
hichkok12 [17]

Answer:

Reflection

Step-by-step explanation: It is reflection because it is the same thing just reflected

7 0
2 years ago
Read 2 more answers
Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0​
solmaris [256]

\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 =   \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 =    -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}

5 0
3 years ago
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