I need to simplify sec^2(x)/sec^2(x)-1

1 answer:

5 0

$\dfrac{\sec^2x}{\sec^2x-1}=\dfrac{\sec^2x}{\tan^2x}=\dfrac{\frac1{\cos^2x}}{\frac{\sin^2x}{\cos^2x}}=\dfrac1{\sin^2x}=\csc^2x$

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Solve each equation. a)2/3-5/6=1/x b)x+6/x=5 c)x+1/3-x-1/2=1 d)x-5/x+1=3/5

Anvisha [2.4K]

Answer:

2 / 3 + 5 / 6 - 1 / 2a.

2 / 3 + 5 / 6 - 1 / 2

= 0,66... + 0,833... - 0,5

= 1,5 - 0,5

= 1

Step-by-step explanation:

sorry I only know the letter A hope I helped anyway

3 0

2 years ago

What is the value of this expression? (−8)^3

REY [17]

(-8)^3 is the same as multiplying -8 by itself 3 times:

-8 x -8 x -8:

-8 x -8 = 64

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4 years ago

3n-8+2(5n+3)=8n+5+4n

DaniilM [7]

3n-8+2(5n+3)=8n+5+4n first I will do the multiplication
3n-8+10n+6=8n+5+4n Now I will simplify
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13n = 12n + 7 then I subtract 12n from both sides
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7 0

4 years ago

Read 2 more answers

The position of a ball after it is kicked can be determined by using the function f left parenthesis x right parenthesis equals

Citrus2011 [14]

Answer:

When kicked, the height of the ball is 1 feet. The highest point for the ball's trajectory is 12 feet.

Step-by-step explanation:

We are given that the height is given by $f(x)=-0.11x^2+2.2x+1$ . The distance between the ball to the point where it was kicked is 0 right at the moment the ball was kicked. So, the height of the ball, when it was kicked is f(0) = -0.11*0 + 2.2*0 +1 = 1.

To determine the highest point, we will proceed as follows. Given a parabola of the form x^2+bx + c, we can complete the square by adding and substracting the factor b^2/4. So, we get that

$x^2+bx+c = x^2+bx+\frac{b^2}{4} - \frac{b^2}{4} +c = (x+\frac{b}{2})^2+c-\frac{b^2}{4}$ .

In this scenario, the highest/lowest points is $c-\frac{b^2}{4}[/tex} (It depends on the coefficient that multiplies x^2. If it is positive, then it is the lowest point, and it is the highest otherwise). Then, we can proceed as follows. [tex] f(x) = -0.11x^2+2.2x+1 = -0.11(x^2-20x)+1$