Question

I need to simplify sec^2(x)/sec^2(x)-1

Answer 1

$\dfrac{\sec^2x}{\sec^2x-1}=\dfrac{\sec^2x}{\tan^2x}=\dfrac{\frac1{\cos^2x}}{\frac{\sin^2x}{\cos^2x}}=\dfrac1{\sin^2x}=\csc^2x$