3 years ago

How do you solve -3y+12=-48

Mathematics

2 answers:

svet-max [94.6K]3 years ago

5 0

Answer:

Step-by-step explanation:

-3y+12=-48 1) Subtract 12 from both sides

1) -3y+12=-48

-12 -12

2) <u>-3y</u>=-<u>60</u> 2) Divide both sides by -3

-3 -3

3) y=20

Dahasolnce [82]3 years ago

4 0

-3y+12=-48
Move 12 to the other side of the equation by subtracting and cancelling out 12
-3y=-36
Then divide by -3 to both sides to get Y by itself
Y=12
A Negative multiplied by a negative equals a positive.

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