3 years ago

How do you solve -3y+12=-48

Mathematics

2 answers:

svet-max [94.6K]3 years ago

5 0

Answer:

Step-by-step explanation:

-3y+12=-48 1) Subtract 12 from both sides

1) -3y+12=-48

-12 -12

2) <u>-3y</u>=-<u>60</u> 2) Divide both sides by -3

-3 -3

3) y=20

Dahasolnce [82]3 years ago

4 0

-3y+12=-48
Move 12 to the other side of the equation by subtracting and cancelling out 12
-3y=-36
Then divide by -3 to both sides to get Y by itself
Y=12
A Negative multiplied by a negative equals a positive.

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Substitution again help please

Vesnalui [34]

Answer:

Step-by-step explanation:

1) 4x -3

x = -7 ;

4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31

x = 14 ;

4x - 3 = 4*14 - 3 = 56 - 3 = 53

x = 0

4x - 3 = 0 - 3 = -3

2) 6 -3x

x = -7 ;

6 - 3x = 6 - 3*(-7) = 6 + 21 = 27

x = 14

6 - 3x = 6 - 3*14 = 6 - 42 = -36

x = 0

6 - 3x = 6 - 0 = 6

$3) \dfrac{3x - 21}{7}\\\\x = -7\\\\\\\dfrac{3*(-7)-21}{7}=\dfrac{-21-21}{7}=\dfrac{-42}{7}=-6\\\\\\x = 14\\\\\dfrac{3*14-21}{7}=\dfrac{42-21}{7}=\dfrac{21}{7}=3\\\\\\x=0\\\\\dfrac{0-21}{7}=\dfrac{-21}{7}=-3\\\\$