For this we will use equation that gives us equation of line that goes through 2 given points.
that equation is:

now we implement our given coordinates.
let Q be point 1 and R be point 2
y - 1 = 6/2(x - 0)
y - 1 = 3x
Answer is b.
Perfect application for the Law of Cosines.
c^2 = a^2 + b^2 - 2ab cos C; here we want C, the angle opposite the 14 m side.
(14 m)^2 = (8 m)^2 + (12 m)^2 - 2(8 m)(12 m) cos C
196 = 64 + 144 - 192 cos C
-12 = -192 cos C, or cos C = 0.0625
Then C = arccos 0.0625 = 1.5083 radians
1.5083 radians 180 deg
= ----------------------- * -------------------
1 3.14159 rad
= 86.417 degrees
= 86 degrees, when rounded off as specified.
hye you want answer of this question ?
Answer:
99g
Step-by-step explanation:
I'm guessing on this one but maybe because a whole number has no remainder