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3 years ago

Please answer this correctly without making mistakes

Mathematics

2 answers:

Mamont248 [21]3 years ago

7 0

Answer:

99g

Step-by-step explanation:

I'm guessing on this one but maybe because a whole number has no remainder

ehidna [41]3 years ago

6 0

Answer:

96.2

Step-by-step explanation:

96.2 is more precise than 99.

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Verify the identity (tan x + 1)^2 + (tan x-1)^2= 2 sec^2 x

Elina [12.6K]

$(\tan x+1)^2+(\tan x-1)^2=2\sec^2x\\\\\text{use}\ \tan x=\dfrac{\sin x}{\cos x}\\\\L_s=\left(\dfrac{\sin x}{\cos x}+\dfrac{\cos x}{\cos x}\right)^2+\left(\dfrac{\sin x}{\cos x}-\dfrac{\cos x}{\cos x}\right)^2\\\\=\left(\dfrac{\sin x+\cos x}{\cos x}\right)^2+\left(\dfrac{\sin x-\cos x}{\cos x}\right)^2\\\\=\dfrac{(\sin x+\cos x)^2}{\cos^2x}+\dfrac{(\sin x-\cos x)^2}{\cos^2x}\\\\\text{use}\ (a\pm b)^2=a^2\pm2ab+b^2$

$=\dfrac{\sin^2x+2\sin x\cos x+\cos^2}{\cos^2x}+\dfrac{\sin^2x-2\sin x\cos x+\cos^2}{\cos^2x}\\\\=\dfrac{\sin^2x+2\sin x\cos x+\cos^2+\sin^2x-2\sin x\cos x+\cos^2}{\cos^2x}\\\\=\dfrac{2\sin^2x+2\cos^2x}{\cos^2x}=\dfrac{2(\sin^2x+\cos^2x)}{\cos^2x}\\\\\text{use}\ \sin^2x+\cos^2x=1\\\\=\dfrac{2(1)}{\cos^2x}=2\cdot\dfrac{1}{\cos^2x}=2\left(\dfrac{1}{\cos x}\right)^2\\\\\text{use}\ \sec x=\dfrac{1}{\cos x}\\\\=2(\sec^2x)=2\sec^2x=R_s\\\\L_s=R_s\Rightarrow The\ identity$

4 0

3 years ago

What is 6 1/4 - 3 1/3

Anettt [7]

Hey There!

Remember, first find the gcf of 4,3 in this problem it is 12.

Steps to solve

1.6 $\frac{1}{4}$ - 3 $\frac{1}{3}$

2.6 $\frac{1}{4}$ - 3 $\frac{1}{3}$ = 2 $\frac{11}{12}$

So, The answer is <span>2 $\frac{11}{12}$ </span>

Hope This Helps :)

6 0

3 years ago

Read 2 more answers

Suppose you have a five dollar off coupon at a fabric store you buy a fabric that cost $10 per yard

Lunna [17]

<h3>Answer:</h3>

1.) 10x-5=y

2.) $85

3.) 5.25 yards of fabric.

<h3>Step-by-step explanation:</h3>

1.) To write an equation for this problem, we need to figure out what every value means:

the variable x, represents the amount of yards of fabric you can buy

the variable y, represents the total amount of money after you found out (x) or the amount of yards of fabric.

1 yard of fabric equals $10, and we have a $5 coupon (-5)

Our equation is:

10x-5=y

This equation represents the relationship between the total cost of fabric, and the amount that you can buy.

2. In order to solve this problem we need to use our equation, one value is given which is 9.

9 represents x, the amount of yards of fabric.

Substitute 9 into x:

10(9)-5=y

<h3>Solve:</h3>

90-5=y

85=y

85 represents the cost of 9 yards of fabric, including the $5 coupon.

3.) This problem is similar to #2, although it's flipped.

The value given is $47.50, which represents (y), the total amount of money after (x) was found out.

But, we need to figure out (x).

Substitute $47.50 into (y):

10(x)-5=$47.50

Next, we need to figure out x by solving the opposite.

Adding the coupon to our answer can represent 10(x).

$47.50+5=52.50

10(x)=52.50

Lastly, divide both sides of the equation by 10.

10(x) / 10=52.50 /10

x=5.25

5.25 represents the amount of yards of fabric purchased if you paid $47.50.

7 0

2 years ago

Heidi Muir, a sporting goods wholesaler, purchased goods from a supplier for $3,400. The

Lena [83]

Answer:

56.44%

Step-by-step explanation:

From the question, we have the following values

% Discount = 3%

Full allowed payment days = 30 days

Discount days = 10 days

1 year = 365 days

The formula for Effective Annual rate or Annual rate in effect =

Discount %/(1-Discount %) x (365 days/(Full allowed payment days - Discount days))

= 3%/(1 - 3%) × (365 days/30 days - 10 days)

= 0.03/(1 - 0.03) × (365/20)

= 0.03/0.97 × (365/20)

= 0.5644329897

Converting to percentage

0.5644329897 × 100

= 56.44329897%

Approximately = 56.44%

Therefore, the annual rate Heidi, in effect, is paying the supplier if she fails to pay the invoice at the end of the discount period is 56.44%

7 0

3 years ago

Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =

vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

$a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2$

$a_1=8$

Find the value of $a_2$

For n=2

$a_2=2.9(a_1)-0.2(a_1)^2$

$a_2=2.9(8)-0.2(8)^2=10.4$

Find the value of $a_3$

For n=3

$a_3=2.9(a_2)-0.2(a_2)^2$

$a_3=2.9(10.4)-0.2(10.4)^2=8.528$

For n=4

$a_4=2.9(a_3)-0.2(a_3)^2$

$a_4=2.9(8.528)-0.2(8.528)^2=10.1858$

For n=5

$a_5=2.9(a_4)-0.2(a_4)^2$

$a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887$

therefore

The population alternates between increasing and decreasing

7 0

3 years ago

Read 2 more answers