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3 years ago

Order these numbers from least to greatest: 1.05, 0.95, 0.75, 1.01

Mathematics

2 answers:

Andru [333]3 years ago

6 0

Answer:

0.75 0.95 1.01 1.05

Step-by-step explanation:

ollegr [7]3 years ago

3 0

Answer:

0.75,0.95,1.01,1.05

Step-by-step explanation:

Thats in order from smallest to biggest.

Hope this helped! If it did, please give me brainliest! That would help a lot! Thanks! :D

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The number 3 was typed into cell A1 of a spreadsheet, while in cells A2-A7, formulas themselves, what would be the value display

beks73 [17]

Answer:

It's C... I just got that............................

Step-by-step explanation:

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3 years ago

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Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

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3 years ago

The number of cartons of apples sold at a store each day for eight days is shown. 30 , 40 , 51 , 30 , 34 , 20, 30, 45 Determine

nikitadnepr [17]

Answer:

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

(30 + 34) /2 = 32

Mode = 30 ( most frequent)

Range = (51 - 20) = 31

Mean = 72

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

Step-by-step explanation:

Given :

1.)

Data: 30 , 40 , 51 , 30 , 34 , 20, 30, 45

Rearranged data : 20, 30, 30, 30, 34, 40, 45, 51

Mean = ΣX / n = 280 / 8

Mean = 35

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

(30 + 34) /2 = 32

Mode = 30 ( most frequent)

Range = (51 - 20) = 31

2.)

90 , 72 , 48 , 84 , 77 , 72, 50, 83

Rearranged data : 48, 50, 72, 72, 77, 83, 84, 90

Mean (m) = ΣX / n = 576 / 8

Mean = 72

Median = 0.5(n + 1)th term

Median = 0.5(9) = 4.5th term

4th + 5term = (72 + 77) /2 = 74.5

Mode = 72 ( most frequent)

Range = (90 - 48) = 42

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3 years ago

PLEASE HELP !!!! brainliest anwser to the person who

Nostrana [21]

The answer is b
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Answer:

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Step-by-step explanation:

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