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3 years ago

Will is W years old.

1 answer:

5 0

Will is W years old.Ben is 3 years older.
Jan is twice as old as Ben.

If you add together the ages of Will, Ben, and Jan the total comes to 41 years

1. W+3= ben age (W+3)*2= Jan age for all three: w+(w+3)+(w+3)2

Sorry i was trying to find a simplier equation and realized i need to do part 2 before i can. I'm trying sorry!

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Homework problem #7: 24567389+35432611=what there is soo much regrouping, could someone show me how to do it?

Natasha_Volkova [10]

Answer:

$24567389+35432611 =60000000$

Step-by-step explanation:

Given

$24567389+35432611 =$

Required

Solve

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

The numbers in parentheses are carried from previous sum

Start from the right

$9 + 1 = 10 \to$ Write 0, carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

$8 + 1 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0

$6 +3 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0

$7+2 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0

$6 +3 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0

$5 +4 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0 0

$4 +5 + (1) = 10 \to$ Write 0 carry 1

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

0 0 0 0 0 0 0

$2 +3 + (1) = 6 \to$ Write 6

2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

6 0 0 0 0 0 0 0

Hence:

$24567389+35432611 =6 0 0 0 0 0 0 0$

8 0

3 years ago

According to industry sources, online banking is expected to take off in the near future. The projected number of households (in

Airida [17]

Answer:

(a) The least-square regression line is: $y=4.662+2.709x$ .

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

$y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

(a)

The formula to compute intercept and slope is:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \end{aligned}$

The values of ∑X, ∑Y, ∑XY and ∑X² are computed in the table below.

Compute the value of intercept and slope as follows:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}$