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kakasveta [241]
4 years ago
12

Sketch one cycle of the cosine function y=-cos 3 theta

Mathematics
2 answers:
likoan [24]4 years ago
8 0

Answer with explanation:

The given cosine function is

   y= - cos 3 (theta)= -3 cos A, where , theta =A.

→→Domain of Cos A

          = All Real number

    = Period is from (-π , π)

Range of Cos A=[-1, 1]

→Domain of Cos 3 A,will be also, all real number.

Period is from,

         [\frac{-\pi}{3},\frac{\pi}{3}]

But range of Cos 3A,will be same as ,Cos A which is equal to ,[-1,1].

→Plotted the graph of ,y=-cos 3 A, having cycle ,

  [\frac{-\pi}{3},\frac{\pi}{3}]

Bumek [7]4 years ago
7 0
The graph of the equation given by y=-cos³θ will be as follows:

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Answer:

a) 4x -y = 2; (1/2, 0), (0, -2)

b) 3x +y = 5; (5/3, 0), (0, 5)

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Step-by-step explanation:

The form you have is ...

y = -Ax +C . . . . . where B = 1

You can simply rearrange the coefficients to get the form you want.

For (a), you can identify -A = 4, so A = -4, and C = -2. In the desired form, the equation is then ...

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I suspect either of the above answers will satisfy your grader, but I like the latter form better. So, the answers below have the equation multiplied by -1 when A is negative to start with.

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The x-intercept is the value C/A, where you do need to pay attention to the signs.

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a) A=-4, C=-2, x-intercept = C/A = -2/-4 = 1/2, y-intercept = C = -2. Equation in standard form is 4x -y = 2

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c) A=-5, C=3, x-intercept = C/A = 3/-5 = -5/3, y-intercept = C = 3. Equation in standard form is 5x -y = -3

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e) A=8, C=-12, x-intercept = C/A = -12/8 = -3/2, y-intercept = C = -12. Equation in standard form is 8x +y = -12

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