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3 years ago

Pls help this packet is driving me crazy!!

Mathematics

2 answers:

Alexeev081 [22]3 years ago

7 0

First, it would be useful to find the rate of change for proportion B. We know it will be in the form y=kx where k is the rate of change, so we just substitute the values from the table:
34.5=k(3)
11.5=k
57.5=k(5)
11.5=k
And as you would guess, 92/8 also equals to 11.5, meaning that the rate of change for proportion B is 11.5. This gives us the equation y=11.5x for proportion B.
Now, we can see that the rate of change for proportion A (9) is 2.5 less than the rate of change for proportion B (11.5).

AleksAgata [21]3 years ago

4 0

Proportion A
The first thing you should know in this case is what the rate of change means.
The rate of change in a linear equation is given by the slope of the line.
For a linear equation, the rate of change is constant.
So we have to:
y = 9x
The slope is:
m = 9
Proportion B
The slope of the line will be:
m = (y2-y1) / (x2-x1)
Substituting values:
m = (57.5-34.5) / (5-3)
m = 11.5
Answer:
The rate of change in proportion A is 2.5 less than in proportion B.

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Step-by-step explanation:

The statement shows a reverse relationship, where an increase in unemployment is following by decrease in potential GDP and can be translated into the following rate:

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3 years ago

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The distance from the fire to tower B is calculated using the law of sines. (Note that this is not a right angled triangle, hence we cannot use trigonometric ratios). The law of sines is expressed as follows;

a/SinA = b/SinB or

a/SinA = c/SinC

Depending on the sides and angles we are given and the ones we are to calculate.

The distance from the fire to tower B is line BC, labeled as a in our diagram. Using the law of sines

a/SinA = c/SinC

(Note also that a is directly facing angle A, c is directly facing angle C, and so on)

a/SinA = c/SinC

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By cross multiplication we now have

a (Sin 74) = 5 (Sin 42)

Divide both sides of the equation by Sin 74 and we now arrive at

a = 5 (Sin 42)/Sin 74

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a = 3.3455/0.9613

a = 3.4802

{rounded to the nearest tenth of a mile, a equals 3.5}

Therefore the distance from tower B to the fire is approximately 3.5 miles

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