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3 years ago

Pls help this packet is driving me crazy!!

Mathematics

2 answers:

Alexeev081 [22]3 years ago

7 0

First, it would be useful to find the rate of change for proportion B. We know it will be in the form y=kx where k is the rate of change, so we just substitute the values from the table:
34.5=k(3)
11.5=k
57.5=k(5)
11.5=k
And as you would guess, 92/8 also equals to 11.5, meaning that the rate of change for proportion B is 11.5. This gives us the equation y=11.5x for proportion B.
Now, we can see that the rate of change for proportion A (9) is 2.5 less than the rate of change for proportion B (11.5).

AleksAgata [21]3 years ago

4 0

Proportion A
The first thing you should know in this case is what the rate of change means.
The rate of change in a linear equation is given by the slope of the line.
For a linear equation, the rate of change is constant.
So we have to:
y = 9x
The slope is:
m = 9
Proportion B
The slope of the line will be:
m = (y2-y1) / (x2-x1)
Substituting values:
m = (57.5-34.5) / (5-3)
m = 11.5
Answer:
The rate of change in proportion A is 2.5 less than in proportion B.

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Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A success is 5 or 6.

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$p = \frac{4}{6} = 0.6667$

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This means that $n = 10$

Find the probability of obtaining at least 8 failures.

This is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951$

$P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867$

$P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174$

Then

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992$

0.2992 = 29.92% probability of obtaining at least 8 failures.

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Step-by-step explanation:

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3 years ago

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Answer:

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hope this helps!

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