We have been given that Sandra throws an object straight up into the air with initial velocity of 38 ft per second from platform that is 30 ft above the ground.

To find the time it will take for object to hit the ground, we will use formula:

$h(t)=-16t^2+v_0t+h_0$ , where, $v_0$ represents initial velocity and $h_0$ represents initial height.

Upon substituting our given initial velocity and initial height, we will get:

$h(t)=-16t^2+38t+30$

We know that object will hit the ground, when height will be 0, so we will equate object's height equal to 0 and solve for t as:

$-16t^2+38t+30=0$

Divide by 2:

$-8t^2+19t+15=0$

Upon using quadratic formula, we will get:

$t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-19\pm\sqrt{19^2-4(-8)(15)}}{2(-8)}$

$t=\frac{-19\pm\sqrt{361+480}}{-16}=\frac{-19\pm\sqrt{841}}{-16}$

$t=\frac{-19\pm29}{-16}$

$t=\frac{-19-29}{-16},t=\frac{-19+29}{-16}$

$t=\frac{-48}{-16},t=\frac{10}{-16}$

$t=3,t=-\frac{5}{8}$

Since time cannot be negative, therefore, it will take 3 seconds for object to hit the ground.

7 0

2 years ago

Could you help me solve this problem ASAP :D

Igoryamba

Answer:

B) 1/4x+1/2=1/3x

Hope this helps!

6 0

3 years ago