9$ for three cans then 9/3= 3 $ per can
Answer:
x = 5
Step-by-step explanation:
√(2x − 1) + 2 = x
√(2x − 1) = x − 2
2x − 1 = (x − 2)²
2x − 1 = x² − 4x + 4
0 = x² − 6x + 5
0 = (x − 1) (x − 5)
x = 1 or 5
Check for extraneous solutions.
√(2(1) − 1) + 2 = 1
√(1) + 2 = 1
3 = 1
No solution
√(2(5) − 1) + 2 = 5
√(9) + 2 = 5
5 = 5
x = 5
Answer:
All non zero digits count in significant digits.
(a) is correct option.
Step-by-step explanation:
Given that,
1.4 has 2 significant digits.
We know that,
Significant digits :
All non zero digits count in significant digits.
All zero which is present in between two significant digits it is also significant.
Leading zero is not count as significant.
Trailing zero is count as significant.
We need to find 1.4 has 2 significant digits as a result of which rule
Using given rules
1.4 has 2 significant digits it is follows the rule of all non zero digits count in significant digits.
Hence, All non zero digits count in significant digits.
(a) is correct option.
27, 36, and 45.
Here's a good nines trick.
9
18
27
36
45
If you pay attention is just adds a ten and minuses a 1 from each number.
8,7,6,5. And 1,2,3,4.
Hope this helps :)
