3 years ago

How does anyone know the answer to this?

1 answer:

katrin2010 [14]3 years ago

6 0

Take the common out of both numerator and denominator and cancel out the terms which are equal.

(8x³ - 2x² - 3x)/(12x²- 9x)

= x(8x² - 2x -3)/3x(4x - 3)

= (8x² - 2x -3)/3(4x - 3)

=(4x-3)(2x+1)/3(4x-3)

= (2x+1)/3

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4 years ago

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3 years ago

If sin θ = square root of three over two, which could not be the value of θ?

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