Original price: $100; Markdown: 32%

Mathematics

2 answers:

Pani-rosa [81]3 years ago

6 0

32% of 100=32
100-32=68
Answer is $68

katen-ka-za [31]3 years ago

5 0

I think the answer would just be $68
all you do is take 32% of 100 which is 32 and take 100-32
100-32=68

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It takes my’khiyah 40 seconds to run 1/3 of a lap. How many laps can she run in 5 minutes

kakasveta [241]

Answer:
number of laps = 5/2 = 2.5 laps

Explanation:
First, we will need to convert the minutes to seconds.
5 minutes = 5 * 60 = 300 seconds

Now, we know that she can run 1/3 of a lap in 40 seconds. To know the number of laps that she can run in 300 seconds, all we have to do is cross multiplication as follows:
40 seconds .................> 1/3 laps
300 seconds ................> ?? laps
number of laps = (300 * 1/3) / 40
number of laps = (100) / 40
number of laps = 5/2 = 2.5 laps

Hope this helps :)

7 0

3 years ago

Two horses are ready to return to their barn after a long workout session at the track. the horses are at coordinates H(1,10) an

ss7ja [257]

The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters

Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.