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Fed [463]
3 years ago
13

In a fruit cocktail, for every 15 ml of orange juice you need 25 ml of apple juice and 10 ml of coconut milk. What proportion of

the cocktail is orange juice?
Give your answer as a fraction in its simplest form.
Mathematics
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

3/10 is orange juice.

Step-by-step explanation:

Step 1: Find the total mL in the concoction

15 + 25 + 10 = 50 mL in a fruit cocktail

Step 2: Find the proportion of orange juice in 1 serving (50 mL) of cocktail

15/50 = 3/10

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Long division method​
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Kevin played a trivia game. Each correct answer is worth 2 / points, and each incorrect answer is worth ­⎯/ point. What was Kevi
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3 years ago
Select all ratios equivalent to 5:10 select all that apply
erastova [34]

Answer:

8:16 and 7:14

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai
Blababa [14]

Let X be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10

where Z follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)

where F_Z(z)=P(Z\le z) denotes the CDF of Z, and F_Z^{-1} denotes the inverse CDF. We have

z_1=F_Z^{-1}(0.90)\approx1.2816

Similarly, because 20% of students obtain less than 40 marks, we have

P(X

so that

P(Z

Then \mu,\sigma are such that

\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma

\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma

and we find

\mu\approx53.8739,\sigma\approx16.4848

3 0
3 years ago
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