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Taya2010 [7]
3 years ago
10

HELP! last one of the day!

Mathematics
1 answer:
quester [9]3 years ago
7 0
The bisector of the angle at A (call it AQ) divides the segment BC into segments BQ:QC having the ratio AB:AC. Use this fact to find x.

.. 9:15 = (2x -1):3x
.. 15(2x -1) = 9*3x . . . . . the product of the means equals the product of extremes
.. 30x -15 = 27x
.. 3x = 15
.. x = 5

___
According to the value of x, the bisector AQ divides the triangle into two isosceles triangles: ABQ, ACQ.
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nika2105 [10]
The answer would be B because range is the highest number take away the lowest number
8 0
3 years ago
Help me please it’s math so... yea.... a b c d e f g h I j k l m n o p q r s t u v w x y z
Ugo [173]
Answer= 16

Work=
1. Multiply each side by 1/5 (aka divide them by 5). This leaves 3, 4 and 9.

2. Add all the sides. 3 + 4 + 9 = 16. That is the perimeter
3 0
4 years ago
Solve the inequality 4(x+1) &lt; 2x+3<br><br> Show steps
OLga [1]
The answer for ure question is x<-1/2

plse mark me brainliest

8 0
3 years ago
Read 2 more answers
What is the equation of the line
Archy [21]

Answer:

y = 4   x = -2

Step-by-step explanation:

3 0
3 years ago
Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
3 years ago
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