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ivann1987 [24]
3 years ago
13

Can you help me with this algebra 2 question please

Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0
Hey!!

here is your answer >>>

(Cube root 27 ) (cube root 64)

cube root of 27 is 3 and cube root of 64 is 4!.

now if we multiply them, we get

(3)(4)

12 !.

The answer is 12!.

Hope my answer helps!
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A function is created to represent the balance on a credit card each month. What restrictions would be made to the range?
Elza [17]
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Point m is located at 4,-2 what is located 2 units for point m
eimsori [14]

Answer:

None

Step-by-step explanation:

Given

m = (4,-2)

Required

Point 2 units from m

There are 4 possible points 2 units from m and they are:

m' = (4+2,-2) = (6,-2)

m" = (4,-2+2) = (4,0)

m'''= (4-2,-2) = (2,-2)

m'''' = (4,-2-2) = (4,-4)

From the graph, we have:

A = (4,2)

B = (-4,2)

C = (2,-3)

None of the points is 2 units from m

7 0
3 years ago
Please answer this question ASAP
Gelneren [198K]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
Sketch the piecewise function shown in the picture. Where is the graph increasing, decreasing, and constant?
sladkih [1.3K]

Answer:

that is a lot of things

Step-by-step explanation:

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3 0
4 years ago
2 sin^2 + sin x - 3 = 0
denpristay [2]

Answer:

x = 2 π n_1 + π/2 for n_1 element Z

or x = π + sin^(-1)(3/2) + 2 π n_2 for n_2 element Z or x = 2 π n_3 - sin^(-1)(3/2) for n_3 element Z

Step-by-step explanation:

Solve for x:

-3 + sin(x) + 2 sin^2(x) = 0

The left hand side factors into a product with two terms:

(sin(x) - 1) (2 sin(x) + 3) = 0

Split into two equations:

sin(x) - 1 = 0 or 2 sin(x) + 3 = 0

Add 1 to both sides:

sin(x) = 1 or 2 sin(x) + 3 = 0

Take the inverse sine of both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin(x) + 3 = 0

Subtract 3 from both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin(x) = -3

Divide both sides by 2:

x = 2 π n_1 + π/2 for n_1 element Z

or sin(x) = -3/2

Take the inverse sine of both sides:

Answer:  x = 2 π n_1 + π/2 for n_1 element Z

or x = π + sin^(-1)(3/2) + 2 π n_2 for n_2 element Z or x = 2 π n_3 - sin^(-1)(3/2) for n_3 element Z

3 0
3 years ago
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