Let the legs of the triangle be a and b, and the hypotenuse c.
Your first instinct might tell you to use the Pythagorean theorem to go about solving this because
![c= \sqrt{a^{2}+b^{2}}](https://tex.z-dn.net/?f=c%3D%20%5Csqrt%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%7D%20)
. This works, but it is slow.
The fastest way to solve this is to recognize that the right triangle is a special triangle where the ratio of the sides are 3:4:5. This means that if the legs are 9 and 12, then the hypotenuse is 15 because 3*3 is 9, 3*4 is 12, and 3*5 is 15.
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Answer:
Step-by-step explanation:
The marked angles form a linear pair, so have a sum of 180°.
(4a +10) +(6a) = 180
10a = 170 . . . . . . . . . . subtract 10
a = 17 . . . . . . . . . . . . . divide by 10
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Then the measure of angle ABC is ...
∠ABC = 4a +10 = 4(17) +10 = 68 +10 . . . . . substitute 17 for 'a'
∠ABC = 78°
-1 and 1/3 because you convert to a regular fraction and get (32/9)/(-8/3), then you flip the fraction and multiply
Answer:
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Step-by-step explanation:
8x - 2y = -8
-5x + 2y = -1
3x = -9
x = -3