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QveST [7]
3 years ago
14

2 sin^2 + sin x - 3 = 0

Mathematics
1 answer:
denpristay [2]3 years ago
3 0

Answer:

x = 2 π n_1 + π/2 for n_1 element Z

or x = π + sin^(-1)(3/2) + 2 π n_2 for n_2 element Z or x = 2 π n_3 - sin^(-1)(3/2) for n_3 element Z

Step-by-step explanation:

Solve for x:

-3 + sin(x) + 2 sin^2(x) = 0

The left hand side factors into a product with two terms:

(sin(x) - 1) (2 sin(x) + 3) = 0

Split into two equations:

sin(x) - 1 = 0 or 2 sin(x) + 3 = 0

Add 1 to both sides:

sin(x) = 1 or 2 sin(x) + 3 = 0

Take the inverse sine of both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin(x) + 3 = 0

Subtract 3 from both sides:

x = 2 π n_1 + π/2 for n_1 element Z

or 2 sin(x) = -3

Divide both sides by 2:

x = 2 π n_1 + π/2 for n_1 element Z

or sin(x) = -3/2

Take the inverse sine of both sides:

Answer:  x = 2 π n_1 + π/2 for n_1 element Z

or x = π + sin^(-1)(3/2) + 2 π n_2 for n_2 element Z or x = 2 π n_3 - sin^(-1)(3/2) for n_3 element Z

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Advocard [28]

Brady studied for 4.5 hours that week

How we determine the total study hours?

The total study hours for Brady is the sum of the hours used in studying on Monday, Tuesday, Wednesday and Thursday.

He studied for 1.5 hours on Monday

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Lastly, he studied for 1 hour on Thursday, the last day

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