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r-ruslan [8.4K]
4 years ago
9

Andrew has aflying disc with a radius of 10 centimeters. What is the circumstance of the disc?

Mathematics
1 answer:
Gnom [1K]4 years ago
7 0
To find out the circumference of a circle, you have to multiply the diameter of the circle with pi.(3.14)

First, to get the diameter of a circle you have to multiply the radius by 2.

10*2=20


The diameter is 20 centimeters.

Then, multiply the diameter by pi.(3.14)

20*3.14=62.8

The circumference is 62.8 centimeters. 
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2w-1 divided by 5+w+2=2w
FromTheMoon [43]

Answer:

(2w-1)/5+w+2=2w

We simplify the equation to the form, which is simple to understand  

(2w-1)/5+w+2=2w

Reorder the terms in parentheses

( + 0.4w-0.2)+w+2=2w

Remove unnecessary parentheses

+ 0.4w-0.2+w+2=2w

We move all terms containing w to the left and all other terms to the right.  

+ 0.4w+1w-2w=0.2-2

We simplify left and right side of the equation.  

-0.6w=-1.8

We divide both sides of the equation by -0.6 to get w.  

w=3

Step-by-step explanation:

6 0
4 years ago
To cover his rectangular backyard, Will needs at least 170.5 square feet of sod.The length of Will’s yard is 15.5 feet.What are
Lostsunrise [7]
170.5/15.5= 11 feet
8 0
3 years ago
I NEED THIS ANSWER ASAP PLEASE!!
d1i1m1o1n [39]

Answer:

<h2>1 3/5 Liters</h2>

Step-by-step explanation:

This question wants us to find 2/5 of 4.

First, change 2/5 to a decimal

0.4 of 4

multiply

0.4 x 4 = 1.6 which in fractional form equals 1 3/5

<em>PLEASE MARK BRAINLIEST</em>

4 0
3 years ago
The table shows the attendance at the art show for the past week.
Vinvika [58]

Answer:

D. 50

Step-by-step explanation:

7*30 - (54+29+22+28+12+15)

=210 - 160

=50

7 0
3 years ago
Read 2 more answers
The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

3rd term = C(4, 2) * a^2b^2

Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

Read more about binomial expansion at

brainly.com/question/13602562

#SPJ1

4 0
1 year ago
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