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MA_775_DIABLO [31]
3 years ago
12

The table shows the cost of taking a rideshare trip. Which description correctly reflects the way the charges are calculated?

Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0

The table is an illustration of a linear function.

The description of the charges is: <em>A)  The ride requires a $14 initial fee, plus 50 cents per mile driven</em>

<em />

The base fee is the charges, when the number of miles is 0

From the table;

y = $14, when x = 0

So, the base fee is $14

Next, we calculate the slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

From the table, we have:

m = \frac{16.5 - 14}{5-0}

m = \frac{2.5}{5}

m = 0.5

The above means that:

The cost per mile is $0.5 (i.e. 50 cents)

Hence, the description of the charges is: <em>A)  The ride requires a $14 initial fee, plus 50 cents per mile driven</em>

<em />

Read more about linear functions at:

brainly.com/question/20286983

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Katyanochek1 [597]

Answer:

Thank you lol. I am so bored right now.

Step-by-step explanation:

3 0
3 years ago
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Can someone please help!!!
RideAnS [48]

Answers:

  • System 1:  x = 3 and y = -5
  • System 2: x = 1 and y = 2

==========================================================

Explanation:

For now, let's focus on system 1.

We have identical copies of "2y" in each equation, which means that if we were to subtract the equations straight down, then the y terms cancel out. That allows us to solve for x.

  • The x terms subtract to 7x-x = 6x
  • The y terms subtract to 0 and go away
  • The right hand sides subtract to 11 minus (-7) = 11-(-7) = 11+7 = 18

After doing those subtractions, we have the new equation 6x = 18 which solves to x = 3. Divide both sides by 6 to isolate x.

Once we know x, we can find out y.

7x+2y = 11

7(3)+2y = 11

21+2y = 11

2y = 11-21

2y = -10

y = -10/2

y = -5

or we can say

x+2y = -7

3+2y = -7

2y = -7-3

2y = -10

y = -10/2

y = -5

We should lead to the same y value either way. This helps confirm we have the correct x value.

Overall, the solution to system 1 is (x,y) = (3, -5)

----------------------------

Now onto system 2.

Unfortunately, we don't have identical y terms this time. But what we can do is double everything in the second equation to go from -x+y = 1 to -2x+2y = 2.

The new equivalent system is

\begin{cases}7x+2y = 11\\-2x+2y = 2\end{cases}

Now we have the same situation as before: Subtract straight down, solve for x.

  • The x terms subtract to 7x-(-2x) = 7x+2x = 9x
  • The y terms go away when subtracting
  • The right hand sides subtract to 11-2 = 9

So we have 9x = 9 and that solves to x = 1.

We'll use this x to find the y value.

7x+2y = 11

7(1)+2y = 11

7+2y = 11

2y = 11-7

2y = 4

y = 4/2

y = 2

Or you could pick on the second equation

-x+y = 1

-1+y = 1

y = 1+1

y = 2

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Explain how to verify that 3(2x + 5) = 9 + 3x and x = –2 are equivalent equations.
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3 times (2x + 5) is 6x + 15.

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