Question

Multiply (x-4)(x^2+6x-5).

Answer 1

Assignment: $\bold{Solve \ Equation: \ \left(x-4\right)\left(x^2+6x-5\right)}$

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Answer: $\boxed{\bold{x^3+2x^2-29x+20}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Distribute Parenthesis

$\bold{xx^2+x\cdot \:6x+x\left(-5\right)+\left(-4\right)x^2+\left(-4\right)\cdot \:6x+\left(-4\right)\left(-5\right)}$

[ Step Two ] Apply Addition / Subtraction Rules

Note: $\bold{Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}$

$\bold{x^2x+6xx-5x-4x^2-4\cdot \:6x+4\cdot \:5}$

[ Step Three ] Simplify $\bold{x^2x+6xx-5x-4x^2-4\cdot \:6x+4\cdot \:5}$

$\bold{x^3+2x^2-29x+20}$

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$\bold{\rightarrow Mordancy \leftarrow}$