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sineoko [7]
2 years ago
8

Alexandria cuts out the net shown and folds it into a number cube. Three faces meet at each corner of the cube. What is the larg

est sum of three numbers that meet at a corner?
Mathematics
1 answer:
ZanzabumX [31]2 years ago
8 0

The largest sum of three numbers that meet at a corner is 15

<h3>How to determine the largest sum?</h3>

The number cube that completes the question is added as an attachment

The largest number in the number cube is 6.

On the number cube, the next largest numbers share the same corner with the number 6

So, the largest set of numbers on the cube are 6, 5, 4

Add the numbers:

Sum = 6 + 5 + 4

Evaluate

Sum = 15

Hence, the largest sum of three numbers that meet at a corner is 15

Read more about number cubes at:

brainly.com/question/474968

#SPJ1

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6x-1=11 solve equation
marin [14]

Answer:

x = 2

Step-by-step explanation:

6x-1=11

Add 1 to each side

6x-1+1=11+1

6x = 12

Divide by 6

6x/6 = 12/6

x = 2

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3 years ago
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Please help me i really need help
joja [24]

Answer:

68

Step-by-step explanation:

15% of 80 is 12 so you subtract 12 from 80 and thats 68.

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3 years ago
Frank stands 450 feet from the base of the Statue of Liberty. If the Statue of Liberty is 306 feet tall, what is the angle of de
kari74 [83]
Let the angle of elevation be θ.


We have a right angled triangle with an opposite of 300.5 ft. (306 - 5.5) and an adjacent of 400 ft. Recalling SOH CAH TOA, tanθ = O/A.
tan(θ) = 300.5/400.
θ = tan^-1(300.5/400).
θ = 36.9°.
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4 years ago
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yarga [219]

36 1/2 to 37.

45.5 - 36 1/2 = 9

those would be the ones I'd click

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3 years ago
Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.​
koban [17]

Answer:

x^2 + 4x + y^2 +8y  =  0

Step-by-step explanation:

Given

A = (-1,-2)

B = (2,4)

AP:BP = 1 : 2

Required

The locus of P

AP:BP = 1 : 2

Express as fraction

\frac{AP}{BP} = \frac{1}{2}

Cross multiply

2AP = BP

Calculate AP and BP using the following distance formula:

d = \sqrt{(x - x_1)^2 + (y - y_1)^2}

So, we have:

2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

Take square of both sides

4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2

Evaluate all squares

4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16

Collect and evaluate like terms

4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20

Open brackets

4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20

Collect like terms

4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y  + 20 - 20 =  0

3x^2 + 12x + 3y^2 +24y  =  0

Divide through by 3

x^2 + 4x + y^2 +8y  =  0

3 0
3 years ago
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