To answer the question, let x be the cost of each hamburger, y be the cost of each medium fries, and z be the cost of each medium drink. The equations that are described in the problem are,
(Miller ) 4x + 3y = 18.69
(James) x + 2y + z = 8.66
(Steven) 2x + y + z = 10.27
Solving simultaneously for the values of the variables give x = 3.36, y = 1.75, and z = 1.8.
Thus, each hamburger costs $3.36. Each medium fries cost $1.75, and each drink costs $1.8.
4.19004 x 10^5
sry I have to write extra stuff to send the answers :)
Answer:
The probability of event A occurs but event B does not occur = P(A)* Probability of event B does not occur = 0.375
Step-by-step explanation:
The probability of event A occurring = 50% = 0.5
The probability of event B occurring = 25% = 0.25
Events A and B are non simultaneous events.
The probability of event B does not occur = 1 - P(B)
= 1- 0.25
= 0.75
So the probability of event A occurs but event B does not occur = P(A)* Probability of event B does not occur
= 0.5*0.75
= 0.375
Thank you.
That would be 1+y≥9
the one and the y go on one side and the nine on the other
