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2 years ago

14

Expanding log functions ㏒3 (3(x+1)(x+2))

1 answer:

Oksanka [162]2 years ago

6 0

Log(ab)=log(a)+log(b)
log_a(a)=1
so

$log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=$ $1+log_3(x+1)+log_3(x+2)$

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Find the value of x so that the function has the given value.<br><br> t(x)=-4x-5 <br><br> t(x)=3

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2 years ago

Lin solved the equation 8(x-3)+7=2x(4-17) incorrectly. Find the errors in her solution. What should her answer have been?

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Answer: The correr solution is $x=\frac{17}{34}$

Step-by-step explanation:

Since the steps in Lin's solution are not shown, we are not able to find her erros. However, we can solve it step by step and find the correct result:

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2 years ago

Need answer to 4 and 5

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Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

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Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

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