Question

Expanding log functions ㏒3 (3(x+1)(x+2))

Answer 1

Log(ab)=log(a)+log(b)
log_a(a)=1
so

$log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=$$1+log_3(x+1)+log_3(x+2)$