4 years ago

Expanding log functions ㏒3 (3(x+1)(x+2))

Mathematics

1 answer:

Oksanka [162]4 years ago

6 0

Log(ab)=log(a)+log(b)
log_a(a)=1
so

$log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=$ $1+log_3(x+1)+log_3(x+2)$

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