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IgorC [24]
3 years ago
14

Expanding log functions ㏒3 (3(x+1)(x+2))

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0
Log(ab)=log(a)+log(b)
log_a(a)=1
so

log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=1+log_3(x+1)+log_3(x+2)
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Write an equation in intercept form of the parabola that passes through the point (3,40) and has x-intercepts −5 and 4.
Maru [420]
The equation of this parabola will have the form f(x) = a(x+5)(x-4), which works out to f(x) = a(x^2 + x - 20).  Since the parabola passes thru (3,40),

40 = a(3^2 + 3 - 20), or 40 = a(-8), so a = -5.

Thus, the equation of this parabola is     y = -5(x^2 + x - 20).
5 0
3 years ago
WHAT IS THE EXPANDED FORM FOR <br><br> 902.604?
murzikaleks [220]

Answer:

(9 × 100) + (2 × 1) + (6 × 0.1) + (4 × 0.001)

Step-by-step explanation:

I am pretty sure

3 0
3 years ago
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How many solutions does the system y=6x-4 and y=4-6x have?
kotegsom [21]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Demichael orders a set of numbers on his
Andru [333]

The numbers are ordered, such that the first number (the largest one) is:

(5 + 1/2)

And the last number (the smaller one) is (5 + 1/3). Only by knowing this, we will see that the correct options are A and C.

We want to see which of the following numbers is not on the list:

A) √25

B) 5.45

C) 5 12  

D) 5.34

One of these numbers can only be in the list if it is larger than  (5 + 1/3) and smaller than (5 + 1/2).

To see this easier, let´s rewrite both of these:

5 + 1/2 = 5 + 0.5 = 5.5

5 + 1/3 = 5 + 0.33 = 5.33

Then if a number is smaller than 5.33, the number can't be in the list.

Here we can see two numbers that are smaller than 5.33

These are:

Option A) √25 = 5 < 5.33

Option C) 5.12 < 5.33

And there is no number larger than 5.5

Concluding, the numbers that are not in Demichael's list are:

√25 and 5.12

If you want to learn more, you can read:

brainly.com/question/7487419

7 0
3 years ago
Find the midpoint of the segment with the given endpoints (3, -5) , (2, 9)
Margarita [4]

Answer:

The coordinates of the midpoint are (5/2 , 2) ....

Step-by-step explanation:

The midpoint is the average values of the endpoint coordinates

We have to find the midpoint of (x1,y1) (x2,y2) = (3, -5) , (2, 9)

We have:

(3, -5) , (2, 9)

To find the coordinates of the mid point we will apply:

M(x1+x2/2 , y1+y2/2)

Now substitute the values:

M(3+2/2, -5+9/2)

M(5/2 , 4/2)

M(5/2 , 2)

Thus the coordinates of the midpoint are (5/2 , 2) ....

6 0
3 years ago
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