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Archy [21]
3 years ago
14

he accounts receivable department at Rick Wing Manufacturing has been having difficulty getting customers to pay the full amount

of their bills. Many customers complain that the bills are not correct and do not reflect the materials that arrived at their receiving docks. The department has decided to implement SPC in its billing process. To set up control​ charts, 10 samples of 50 bills each were taken over a​ month's time and the items on the bills checked against the bill of lading sent by the​ company's shipping department to determine the number of bills that were not correct. The results​ were: Sample No. 1 2 3 4 5 6 7 8 9 10 No. of Incorrect Bills 9 2 14 1 3 2 3 4 9 0 ​a) The value of mean fraction defective ​(p overbar​) ​= nothing ​(enter your response as a fraction between 0 and​ 1, rounded to four decimal​ places).

Mathematics
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

0.094 or 9.4%

Step-by-step explanation:

We have to compute the proportion of defective bills in each batch and then calculate a weighted average.

Let first construct a table like the one attached (see picture)

The value of the mean fraction defective is

\large \bar p = \frac{47}{500}=0.094=9.4\%

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2 years ago
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Help!!! 10pts!!
horsena [70]
It's a bit of a bummer to have to work through all of these to find the answer. That a lot of slope calculations (or graphing, or whatever). When there are this many, a spreadsheet or other machine help can make it easier.

The correct choice is the last one, XYZ, with vertex X being where the right angle is located.

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3 years ago
What is the slope of the line that passes through these points in decimal form
mestny [16]

Answer:

-1.25

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(3,8)   (7,3)

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FYI: watch some videos on Khan academy on finding slope

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2 years ago
Which quadratic rule represents the data in the table?
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3 years ago
#18. estimate the perimeter and the area of the shaded figure to the nearest tenth
Gelneren [198K]

Answer:

Area = 22.3 m^2

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Step-by-step explanation:

Perimeter = __ m

Area __ m^2

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The area of the square is 4,

The area of the semicircle is 14.1,

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