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Alex777 [14]
2 years ago
8

you go out to breakfast and order a meal that costs $7.24 and a coffee that costs $2.65. there is a 6.4% sales tax and you leave

a 25% tip. what is the total cost of the meal?
Mathematics
1 answer:
Sauron [17]2 years ago
4 0

Answer: total cost is $13

Step-by-step explanation:

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Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Irina18 [472]

Answer:

x = 97.6

Step-by-step explanation:

cos = adjacent over hypotenuse

cos(55)=\frac{56}{x}

* multiply each side by x *

cos(55)*x=xcos(55)\\\frac{56}{x} *x=56\\56=xcos(55)

* divide each side by cos ( 55 ) *

\frac{xcos(55)}{cos(55)} =x\\\frac{56}{cos(55)} =97.63302055

we're left with x = 97.63302055

Our last step is to round to the nearest tenth of a foot

We get that x = 97.6

4 0
3 years ago
A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria
Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

9000 = 400e^{k4}.

Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

6 0
3 years ago
Whats the slope for (-4,-1) and (-2,-5)
velikii [3]

Answer:

Alright use the slope formula Which gives you a Answer of

m = -2 Hope this helps :)

Step-by-step explanation:


8 0
3 years ago
System<br> of equation<br> y+2=4
jolli1 [7]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Please do this one first!! its calling YOUR name!! its easy a cake
Finger [1]
I think the range is 18
6 0
3 years ago
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