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3 years ago

Which relationships have the same constant of proportionality between y and x as the following table.

Mathematics

1 answer:

blondinia [14]3 years ago

4 0

Answer:

A, D, E

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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4 years ago

The legs of a right triangle measure 4 and 6 inches. The area of the triangle is

liraira [26]

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4 years ago

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Use place value to find the product

Alina [70]

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3 years ago

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X² + y² = 49

cluponka [151]

Answer:

1....y=7

2...x=7

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3 years ago

Choose the correct vertex of the function f(x) = x2 - X + 2.

8_murik_8 [283]

Answer:

The vertex of the function is $(\frac{1}{2}, \frac{7}{4})$

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

$f(x) = ax^{2} + bx + c$

It's vertex is the point $(x_{v}, y_{v})$

In which

$x_{v} = -\frac{b}{2a}$

$y_{v} = -\frac{\Delta}{4a}$

Where

$\Delta = b^2-4ac$

If a<0, the vertex is a maximum point, that is, the maximum value happens at $x_{v}$ , and it's value is $y_{v}$ .

f(x) = x² - X + 2.

Quadratic equation with $a = 1, b = -1, c = 2$

$\Delta = b^2-4ac = (-1)^2 - 4(1)(2) = 1 - 8 = -7$

$x_{v} = -\frac{(-1)}{2} = \frac{1}{2}$

$y_{v} = -\frac{-7}{4} = \frac{7}{4}$

The vertex of the function is $(\frac{1}{2}, \frac{7}{4})$

4 0

3 years ago