Hey there!
What you do is find how much was taken off and add that to the price
60*.2= 12
12 was taken off of the original price
Now add:
60+12= 72
So the regular price was $72
Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:
![y = -\frac{6500}{5}x+7000](https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac%7B6500%7D%7B5%7Dx%2B7000)
and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:
![y=-\frac{6500}{5}\cdot 2 + 7000= 4400](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B6500%7D%7B5%7D%5Ccdot%202%20%2B%207000%3D%204400)
Answer:
yes but no
Step-by-step explanation:
um well that is a lot by not if there is a bunch of people doing it.
Answer:
27 =x
Step-by-step explanation:
The two angles are vertical angles and vertical angles are equal
4x+7 = 5(x-4)
Distribute
4x+7 = 5x-20
Subtract 4x from each side
4x+7-4x = 5x-4x-20
7 = x-20
Add 20 to each side
7+20 = x-20+20
27 =x
<h2>
Answer:</h2>
![\boxed{y=-3}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D-3%7D)
<h2>
Step-by-step explanation:</h2>
The graph of this parabola is shown below. From this graph we know that:
VERTEX:
![(h,k)=(0,0)](https://tex.z-dn.net/?f=%28h%2Ck%29%3D%280%2C0%29)
DIRECTIX:
Since the vertex lies on the origin and the parabola opens upward, then the standard form of this parabola is:
![x^2=4py](https://tex.z-dn.net/?f=x%5E2%3D4py)
So:
![y=\frac{1}{12}x^2 \\ \\ \therefore 12y=x^2 \ or \ x^2=12y \\ \\ \\ Then: \\ \\ 4p=12 \therefore p=3](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B12%7Dx%5E2%20%5C%5C%20%5C%5C%20%5Ctherefore%2012y%3Dx%5E2%20%5C%20or%20%5C%20x%5E2%3D12y%20%5C%5C%20%5C%5C%20%5C%5C%20Then%3A%20%5C%5C%20%5C%5C%204p%3D12%20%5Ctherefore%20p%3D3)
Then the directrix is:
![y=k-p \\ \\ \therefore y=0-3 \therefore \boxed{y=-3}](https://tex.z-dn.net/?f=y%3Dk-p%20%5C%5C%20%5C%5C%20%5Ctherefore%20y%3D0-3%20%5Ctherefore%20%5Cboxed%7By%3D-3%7D)