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PSYCHO15rus [73]
3 years ago
6

Which proportion can be used to find 65% of 90?

Mathematics
1 answer:
ra1l [238]3 years ago
3 0
X 65%
———— = ———-
90 100

1) multiply across
90 • 65 = 5,850

2) divide what’s left over.
5,850 / 100 = 58.5
You might be interested in
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains
AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

f(x) = (1-p)^{x}p

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

\mu = \frac{1-p}{p}

The standard deviation of the geometric distribution is given by the following formula:

\sigma = \sqrt{\frac{1-p}{p^{2}}

In this problem, we have that:

p = 0.383

So

\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61

\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05

(a) What is the probability that a drought lasts exactly 3 intervals?

This is f(3)

f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

f(3) = 0.09

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

0.855 + P(X \geq 4) = 1

P(X \geq 4) = 0.145

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0
3 years ago
Calculating area of rectangle with a diagonal of 5m height of 3m and length of 4m
bagirrra123 [75]

Answer:

area = 12 m²

Step-by-step explanation:

area = L x W

area = 4 x 3 = 12 m²

8 0
2 years ago
Read 2 more answers
Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s
Snezhnost [94]

Answer. First option: t > 6.25


Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



5 0
3 years ago
Read 2 more answers
Can someone answer plz
NeX [460]

1.D 2. A 3.C 4.D

1 Is the monomial as it only contains one expression.

2. Is the difference of squares because something squared minus something squared.

3. Is standard because it is of the form

a_nx^n+ a_{n-1}x^{n-1}+...+a_1x+a_0

4. We know D is the not the monomial simply because its power is negative which means it does not fit the definition of a polynomial.

3 0
2 years ago
Find the 72nd term of the arithmetic sequence -27, -11, 5, ...
MAXImum [283]

Step-by-step explanation:

first identify the common difference

The first term which i will define by u⁰=-27

u¹=u⁰+(1)d where d is the common difference and u¹ is the second term

u¹=-27+d

-11=-27+d

d=27-11=16

The 72nd term would be u⁷¹ since we started from u⁰ as our first term:

Use the explicit relation given by:

u(n)=u⁰+(n)d

u(71)=-27+71(d)

u⁷¹=-27+71(16)

u⁷¹=-27+1136

u⁷¹=1109

8 0
2 years ago
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