A jewelry company prints a hidden logo watermark. The watermark is a chord that is 0.8 cm from the center of a circular ring tha
t has a r = 3 cm radius. What is the length of the chord to the nearest tenth?
1 answer:
Answer:
length of chord is 6cm
Step-by-step explanation:
Here, we are to calculate the length of the chord.
It should be understood that the chord has a length of 0.8cm from the center of the circle of radius 3cm, thereby forming two right-angled triangles with the radius 3cm being the hypotenuse of each and 0.8cm being the height of each.
Now, the chord is divided into 2 by this height dropping from the center of the circle. To calculate the first half, we use Pythagoras’ theorem with 3cm being hypotenuse and 0.8cm being the other side.
mathematically;
3^2 = 0.8^2 + l^2
9 = 0.64 + l^2
l^2 = 9-0.64
l^2 = 8.36
l = √(8.36)
l = 2.89 approximately
The length of the chord would be 2l = 2 * 2.89 = 5.78 cm which is 6cm to the nearest length
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Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,
which is a cubic polynomial in with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).
Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.
f'(x) = 3x² - 1 = 0 ⇒ x = ±1/√3
So, we have three subsets over which f(x) can be considered invertible.
• (-∞, -1/√3)
• (-1/√3, 1/√3)
• (1/√3, ∞)
By the inverse function theorem,
where f(a) = b.
Solve f(x) = 2 for x :
x³ - x + 2 = 2
x³ - x = 0
x (x² - 1) = 0
x (x - 1) (x + 1) = 0
x = 0 or x = 1 or x = -1
Then can be one of
• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);
• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or
• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)
Hope it helps.....................
Answer: The answer is 62.32
Step-by-step explanation:
See attachment
