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Lynna [10]
3 years ago
5

1) y=7x- 12-3x+4y=2​

Mathematics
1 answer:
ioda3 years ago
8 0

Answer:

x = 2

y = 2

Step-by-step explanation:

Given that:

y=7x- 12  -------- eq1

-3x+4y=2​ ------ eq2

eq1 can be written as:

7x - y = 12

Multiplying this equation by 4 we get:

28x - 4y = 48 --------- eq3

Adding eq2 and eq3 we get:

28x - 3x = 48+ 2

25x = 50

x = 2

Now put this equation in eq1

y = 7(2) - 12

y = 14 - 12

y = 2

i hope it will help you!

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3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

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For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

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Answer: 9.1

Step-by-step explanation:

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Answer:

0.30

Step-by-step explanation:

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