Let quarters = q and
Dimes = d
We have 741 coins total so q + d = 741
Since quarters are 25 cents and Dimes are 10 cents then
25q + 10d = 10725 cents
Now we have 2 equations that we can solve using addition or substitution.
Using addition, first multiply the first equation by -10
-10 (q+d) = 741 (-10)
-10q - 10d = -7410
Now add the equations together
(-10q -10d = -7410)
+ (25q + 10d =10725)
________________
15q = 3315
q = 3315 / 15
q = 221
this is the number of quarters
Now plug this back into the original equation
q + d = 741
221 + d = 741
d = 741 - 221
d = 520
There are 520 dimes
Answer:
-3
Step-by-step explanation:
-3 is the highest number in the set
Tom wants to save at least $2000. He already got $375. Let x be the amount he still needs to save.
375 + x >= 2000
Subtract 375 from both sides
375 + x - 375 >= 2000 - 375
x >= 1625
So he still needs to save at least $1625.
Hope this helps! :)
Answer: 24
Step-by-step explanation:
Follow PEMDAS. Parentheses: 16+a, which is 18. There are no exponents so move on to multiplication. 6b. B is equal to 3, and 6x3 is 18. Next, division. 18/3 is 6. Now do addition so add together 18+6 which is 24.
