Answer:
The general solution is
Step-by-step explanation:
Given differential equation is
y''-4y'+4y=0
and
To find the we are applying the following formula,
The general form of equation is
y''+P(x)y'+Q(x)y=0
Comparing the general form of the differential equation to the given differential equation,
So, P(x)= - 4
The general solution is
Given
two angles (150° and 12°) and the shortest side (12 cm) of a triangle
Find
the second-shortest side
Solution
Strategy: Make use of the Law of Sines to find missing side lengths when angles are known. To find the third angle, make use of the sum of angles of a triangle.
The sum of angles of a triangle is 180°, so we have
... 150° + 12° + C = 180°
... C = 180° - 162° = 18°
The law of sines tells us
... c/sin(C) = b/sin(B)
... c = sin(C)·b/sin(B) = sin(18°)·(10 cm)/sin(12°)
... c ≈ 14.9 cm
_____
We are calling the sides a, b, c. We are calling the angles opposite those sides A, B, and C.
The blue line (B)
You can count by going up 2 over 1