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2 years ago

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Stan invests $5000, some at 6% interest and the rest at 4.5% interest. If x is the amount he invests at 6%, then the amount inve

sted at 4.5% can be expressed as
A) .045x.
B) 10.5x.
C) 5000 - x.
D) 5000 + x.

1 answer:

Bumek [7]2 years ago

8 0

Let's say that Stan invested $1500 at 6%. To find how much he invested at 4.5% would be 5000 - 1500 = $3500. Now we have a pattern. Now let's say stan invested x dollars. Even though it is unknown, we can set up how much is left. So subtract x from 5000 or 5000 - x which is C

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Please answer this correctly

brilliants [131]

Answer:

3 years 8 month

Step-by-step explanation:

Given 7 years 6 months - 3 years 10 months

Step 1: Firstly we should subtract months from months then after from year to year.

Step 2: 6 months is less than 10 months so we have to borrow 1 year and add it to the months.

Step 3: Adding 1 year to 6 months we get 18 months.

Step 4: Now we have to subtract 3 years 10 months from 6 years 18 months.

$6\ years\ 18\ months-3\ years\ 10\ months=3\ years\ 8\ months$

Step 5: After subtracting we get 3 years 8 months.

Thus the answer is 3 years 8 months.

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2 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

2 years ago

Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

sdas [7]

There asking for the equation, and the possible answers are

y = 2x + 6 y = −one halfx + 3 y = −one halfx + 6 y = 2x + 3

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2 years ago

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denpristay [2]

7245000...hope that helps

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bearhunter [10]

The answer to your question is Y

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3 years ago