Answer:
W = 15900 ft.lb
Step-by-step explanation:
From the given information.
Consider y to be the distance from the ground towards the bucket of the cement.
At height y, suppose the bucket is lifted by Δy.
Then, the workdone can be = 500Δy + 0.5(75 - y) Δy
where;
The bucket of the cement = 500Δy
The remaining of the rope = 0.5(75 - y) Δy
However; the workdone (W) can be calculated as:
W = 15000 + 0.5 ( 2250 - 450)
W = 15000 + 900
W = 15900 ft.lb
Multiplication gives
us distribution over the products, so
(a′+b+d′) (a′+b+c′+f′)
= a′ (a′+b+c′+f′) + b (a′+b+c′+f′) + d′ (a′+b+c′+f′)
And then you can
then distribute again each of the factors on the right.
Then you should simplify
in any given number of ways. To take as an example, you have a′b and ba′,
and since a′b + a′b = a′b + a′b = a′b, you can just drop one of them.
Since bb = b, you can rewrite bb as b and etc.
So in the end
part we should arrive at a sum of products. Then you can just invert. For
example, if at the end you had:
p′ = a′b + bc′ +
d′f ′+ a′f′
Then we would
have
p = p′′ = (a′b +
bc′ + d′f′ + a′f′)′ = (a′b)′⋅(bc′)′⋅(d′f′)′⋅(a′f′)′
Then applying De
Morgan's laws to each of the factors, e.g., (a′b)′ = a+b′, so we would
have
p = (a+b′)⋅(b′+c)⋅(d+f)⋅(a+f)
which is a
product of sums.
The slope is 2.
Equation if needed: y= 2x + 1
Answer:
4n+5= 6n
4n-5 = 4n
Step-by-step explanation:
down ratio is the first series is the secondand fourth series is the second series
Answer:
5000 meters
Step-by-step explanation:
1 km = 1000 m
5 km = 1000 × 5 = 5000 meters
Therefore there are 5000 meters in a 5 km race.
