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beks73 [17]
3 years ago
8

Devin borrowed $1,058 at 13 percent for nine months. What will he pay in interest?

Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Devin borrowed $1,058 at 13 percent for nine months.

We have to calculate the interest paid.

Interest = \frac{P \times R \times T}{100}

Substituting the values of

Principal = $1058

Rate = 13%

Time = 9 months = \frac{9}{12} year

Interest = \frac{1058 \times 13 \times 9}{12 \times 100}

Interest = 103.155

= 103.16

So, Devin will pay 103.16 as the interest.

Therefore, Option A is the correct answer.

Nataly [62]3 years ago
3 0
A, 103.16 Hope this is right!
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) a pair of fair dice is rolled. what is the probability that the sum of the top faces is a number 10 or greater?
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Hope this helps.
5 0
3 years ago
Apply the distributive property to create an equivalent expression.
VMariaS [17]

Answer:

12e minus 6f minus 8

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
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5 0
3 years ago
You buy shrimp at the market.
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8 0
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