M1V1 + M2V2 = M1V1' + M2V2'
where:
M1 is the mass of the large marble = 0.05 kg
V1 is the initial velocity of the large marble = 0.6 m/sec
M2 is the mass of the small marble = 0.03 kg
V2 is the initial velocity of the small marble = 0 m/sec (marble is at rest)
V1' is the final velocity of the large marble = -0.2 m/sec
V2' is the final velocity of the small marble that we want to calculate
Substitute with the givens in the above equation to get V2' as follows:
M1V1 + M2V2 = M1V1' + M2V2'
(0.05)(0.6) + (0.03)(0) = (0.05)(-0.2) + 0.03V2'
0.03 = -0.01 + 0.03V2'
0.03V2' = 0.03+0.01 = 0.04
V2' = 0.04/0.03
V2' = 1.334 m/sec
Use cross multiplication to answer this. Since there is 2.5 grams in 1 serving, you would set it up with grams of fat being the numerator and servings being the denominator, like this:
2.5 / 1 = x / 3.75
Then just do the algebra:
(2.5 / 1) * (3.75) = x
And the answer is:
9.375 = x
Answer:
(a). The work done is 7001 MeV.
(b). The momentum of this proton is .
Explanation:
Given that,
Speed = 0.993 c
We need to calculate the work done
Using work energy theorem
The work done is equal to the kinetic energy relative to the proton
Put the value into the formula
(b). We need to calculate the momentum of this proton
Using formula of momentum
Put the value into the formula
Hence, (a). The work done is 7001 MeV.
(b). The momentum of this proton is .