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4 years ago

Which is the correct quark pairing

Physics

2 answers:

Ugo [173]4 years ago

8 0

The second answer is right. T,B U,D, S,C.

White raven [17]4 years ago

4 0

Answer: I believe the answer is b

Explanation:

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A missile is moving 1350 m/s at a 25.0 angle

murzikaleks [220]

I will answer both versions assuming what you want to know is the distance it travels up from and over the ground. and how long until it reaches space. 540 meters per second up and over. to reach space which is 100km above sea level, it would take about 5400 minutes

4 0

3 years ago

A student's room has a TV (250 W) ,heater (1150 W) and lamp (200 W) Electricity costs 10 fills per KWh. Calculate how much it wo

Yuki888 [10]

Answer:

Cost = 40 fills

Explanation:

First, we will calculate the total power consumed by all appliances:

$Power = P_{TV}+P_{heater}+P_{lamp}\\Power = 250\ W+1150\ W+200\ W\\Power = 1600\ W = 1.6\ KW$

Now, we will calculate the energy required:

$Energy = (Power)(Time)\\Energy = (1.6\ KW)(2.5 h)\\Energy = 4 KWh\\$

Now, for the cost we use the following formula:

$Cost = (Energy)(Unit\ Cost)\\Cost = (4\ KWh)(10\ fills/KWh)\\$

<u>Cost = 40 fills</u>

6 0

3 years ago

A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have? The car has J of kinetic

konstantin123 [22]

The kinetic energy of an object is given by:
$K= \frac{1}{2}mv^2$
where m is the mass of the object and v its velocity.

The car in this problem has a mass of m=600 kg and a velocity of v=10 m/s, therefore if we put these numbers into the equation, we find the kinetic energy of the car:
$K= \frac{1}{2}mv^2= \frac{1}{2}(600 kg)(10 m/s)^2=30000 J$

5 0

3 years ago

Please solve this problem inelastic collision

S_A_V [24]

It will crash at a speed of 5 m/s and that's basically it.

7 0

4 years ago

A 30-kg shopping cart full of groceries sitting at the top of

Evgesh-ka [11]

Answer:

0.0102 m or 1 cm

Explanation:

Let g = 10m/s2

The potential energy of the shopping cart of the top of the hill is:

$E_p = mgh = 30*9.8*2 = 600 J$

When the cart gets to the bottom of the hill, all this potential energy is converted to kinetic energy:

$E_k = mv^2/2 = 600 J$

$v^2 = \frac{600*2}{30} = 40$

$v = \sqrt{39.2} = 6.324 m/s$

As the cart stop due to the stump, the can of peaches flies with the same speed.

By Newton's 3rd law, the car would exert a 490N force on the can too

The deceleration of the can would then be:

$a = F/m = 490/0.25 = 1960 m/s^2$

This force would stop the can, but not without making a dent, aka a traveled distance on the car skin

We can use the following equation of motion to find out the distance traveled by the can:

$v^2 - v_0^2 = 2a\Delta s$

where v = 0 m/s is the final velocity of the can when it stops, $v_0^2$ = 40m/s is the initial velocity of the can when it hits, a = -1960 m/s2 is the deceleration of the can, and $\Delta s$ is the distance traveled, which we care looking for:

$0 - 40 = 2*(-1960)*\Delta s$

$\Delta s = \frac{40}{2*1960} = 0.0102 m$ or 1 cm

3 0

3 years ago