Answer
given,
mass of the shuffleboard disk = 0.42 kg
speed of the cue is increased to = 4.2 m/s
acceleration takes over 2 m then acceleration is zero.
the disk additionally slide to 12 m
final speed of disk = 0 m/s
a) increase in thermal energy
b) 
F_f is the frictional force
increase in thermal energy for entire movement of 14 m
c) Work done on the disk by the cue
W = 3.704 + 0.616
W = 4.32 J
We know, U = mgh
Substitute the known values,
19.6 = m * 9.8 * 8
m = 19.6 / 78.4
m = 1/4
In short, Your Answer would be 1/4 Kg
Hope this helps!
Answer:
Let M1 = 8 kg and M2 = 34 kg
F = M a = (M1 + M2) a
F = M2 g the net force accelerating the system
M2 g = (M1 + M2) a
a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2
Answer:
reflection of water ,sound and water waves etc
The answer is: "
44 
km " ;
or; write as: "
44.333 km " .
___________________________________________________________Explanation:___________________________________________________________(70 km + 63 km) ÷ (2 + 1 ) = 133 km ÷ 3 = "
44 km " ;
or; write as: "
44.333 km " .
___________________________________________________________
