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atroni [7]
3 years ago
10

When a class took a math test, 15% of the class failed, 25% made some mistakes (but didn’t fail), and 24 students got perfect sc

ores. How many students were in the class?
Mathematics
2 answers:
mart [117]3 years ago
5 0

Answer:

There are 40 students in the class.

Step-by-step explanation:

We are given the following in the question:

Percentage of class that failed = 15%

Percentage of class that made mistakes but did not fail = 25%

Number of students that got perfect score = 24

Percentage of students that got perfect score =

100\%-\text{Percentage of class that failed}-\text{Percentage of class that made mistakes but did not fail}\\= 100\%-15\%-25\%\\= 60\%

Let x be the total number of students in the class.

Then, we can write:

60\% \text{ of } x = 24\\60\% \times x = 24\\\\\displaystyle\frac{60}{100}\times x = 24\\\\x = 24\times \frac{100}{60}\\\\x = 40

Thus, there are 40 students in the class.

zvonat [6]3 years ago
4 0

Answer:

40

Step-by-step explanation:

i did it before

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Answer:

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Step-by-step explanation:

Applicable relations are ...

  C = 2πr . . . . . . . r = radius, C = circumference

  LA = 1/2·Ch . . . . h = slant height, LA = lateral area

  SA = πr² +LA . . . SA = total surface area

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1. Given r and SA, we can find the other measures as ...

  LA = SA -πr² = 50 ft² -π(3 ft)² ≈ 21.7 ft²

  C = 2πr = 2π(3 ft) ≈ 18.8 ft

  h = 2·LA/C ≈ 2·21.7 ft²/(18.8 ft) ≈ 2.3 ft

(Please note that for calculations using intermediate results, we used the full-precision values of those results, not the rounded ones. Rounding is always the last operation. Please note, too, that we have used a value for π sufficient to ensure accuracy in all the digits shown here.)

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2. Given C and LA, we can find the other measures as ...

  h = 2·LA/C = 2(176 in²)/(44 in) = 8 in

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  SA = LA +πr² = LA +rC/2 ≈ 176 in² +(7.0 in)(44 in)/2 ≈ 330.1 in²

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Answer:

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Step-by-step explanation:

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