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Ivan
3 years ago
5

Divide 3/16 by 5/2 EXPLAIN ANSWER PLZ! AND FAST! I WILL NAME YOU BRANLIEST!

Mathematics
2 answers:
Travka [436]3 years ago
8 0

Use the KCF method to divide

3/6  /  5/2 =  3/6 x 2/5, which equals 1/5

Hope that helps :)

Nastasia [14]3 years ago
6 0

Here is you're answer:

In order to answer this question you must use KCF:

  • \frac{3}{16} \div \frac{5}{2}
  • Input KCF:
  • \frac{3}{16} \times \frac{2}{5}
  • Now solve:
  • \frac{3}{16} \times \frac{2}{5} = \frac{6}{80}
  • Simplify:
  • \frac{6}{80} \div 2 = \frac{3}{40}
  • = \frac{3}{40}

Therefore you're answer is "3/40."

Hope this helps!

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Wich number line represents the solution set for the 2x-6>6(x-2)+8
Fantom [35]
Well...
2x-6x>-12+8-6
-4x>-10
Attention! ">" change for "<" because we multiply both members for (-1)
x<10/4
It is the same to say (-infinite ; 10/4) or (-infinite ; 5/2) or (-infinite ; 2.5)
Good luck!
M.
3 0
3 years ago
The recipe for Perfect Purple Water says, "Mix 8 ml of blue water with 3 ml of red water." Jada mixes 24 ml of blue water with 9
cluponka [151]

Answer:Jada will get same shade as Perfect Purple Water

Step-by-step explanation:

STEP 1

To get the right  recipe for Perfect purple water, every new mixture must have an equivalent ratio as the ideal mixture

The ideal mixture is given as

8ml  blue water and 3 ml red water.

Step 2

Andre mixes 16ml blue water with 9ml red water

\frac{8ml}{3ml} is not equivalent to \frac{16ml}{9ml}

Because dividing Andre's mixture  by a common value  will  not give  the equivalent ratio of the ideal recipe

\frac{16ml}{9ml}  \frac{/}{/}  \frac{3}{3} =\frac{5.3ml}{3ml}  

Jada mixes 24ml blue water with 9ml red water

\frac{8ml}{3ml} is equivalent to \frac{24ml}{9ml}

Because dividing Jada's mixture  by a common value  gives the equivalent ratio of the ideal recipe

\frac{24ml}{9ml}  \frac{/}{/}  \frac{3}{3} =\frac{8ml}{3ml}  

This shows that Jada got the right recipe and will get  same shade as Perfect Purple Water but in a higher quantity, 3 times the right recipe for  Perfect Purple Water

7 0
3 years ago
Which of the following best describes the relationship between (x-3) and the polynomial x^3+4x^2+2?
Anna71 [15]
This is the concept of polynomials, to get the relationship between the (x-3) and (x^3+4x^2+2) we shall proceed as follows;
we first test if (x-3) is a polynomial;
x-3=0
thus;
x=3
substituting the value of x in the polynomial we get:
(3)^3+4(3)^2+2
=65
since the result is not equal to 0, we conclude that there is no relationship between (x-3) and the polynomial. The answer is B. (X-3) is not a factor
7 0
3 years ago
Read 2 more answers
Autumn measures the angle of elevation from the ground to the top of an 18-foot tall tree as 27°. To the nearest tenth of a foot
leonid [27]

Answer: she is 35.3 feet from the tree.

Step-by-step explanation:

Assuming her line of sight to the top of the tree is a straight line, then a right angle triangle is formed. The height of the tree, h represents the opposite side of the right angle triangle. Her distance, h from the tree represents the adjacent side of the right angle triangle. To determine h, we would apply the tangent trigonometric ratio.

Tan θ = opposite side/adjacent side. Therefore,

Tan 27 = 18/h

h = 18/tan27 = 18/0.51

h = 35.3 feet

7 0
4 years ago
Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''
Nonamiya [84]

Answer:

a-e^x,e^{-x}

b-x^{-2}

c-x^3

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

D^2-1=0

(D-1)(D+1)=0

D=1,-1

Then , the solution of given differential equation

y=e^x,y=e^{-x}

2.7x^2y''+14xy'-14 y=0

Y=y=x^3

y=3x^2

y''=6x

Substitute in the given differential equation

42x^3+42x^3-14x^3\neq 0

Hence, x^3 is not a solution of given differential equation

e^x,e^{-x} are also not a solution of given differential equation.

y=x^{-2}

y'=-2x^{-3}

y''=6x^{-4}

Substitute the values in the differential equation

7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}

=42x^{-2}-28x^{-2}-14x^{-2}=0

Hence, x^{-2} is a solution of given differential equation.

c.7x^2y''-42y=0

y=x^3

y'=3x^2

y''=6x

Substitute the values in the differential equation

42x^3-42x^3=0

Hence, x^3 is a solution of given differential equation.

a-e^x,e^{-x}

b-x^{-2}

c-x^3

6 0
4 years ago
Read 2 more answers
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