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Brums [2.3K]
3 years ago
7

Given a rectangle with a length of 36 and a width of 9 which rectangle is similar ​

Mathematics
1 answer:
uysha [10]3 years ago
6 0
Do you have an image?
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How many times can 91 go into 357
vova2212 [387]
91 can go into 357 3 times
4 0
3 years ago
Determine whether the improper integral converges or diverges.
NISA [10]
The improper integral diverges
3 0
4 years ago
Keith wants to make cupcakes to make cupcakes he needs 5/8 of a cup of flour per batch of cupcakes if Keith has 5 cups of flour
castortr0y [4]

Answer:

she can make 8 batches

Step-by-step explanation:

In this question , we are concerned with calculating the number of batches of cupcakes keith can make.

To make a batch, 5/8 of a cup is required.

Now she has 5 cups. The number of batches she can make will be 5/(5/8) = 5 * 8/5 = 8

4 0
4 years ago
The rabbit population in Scott County, which is currently at 2,900 rabbits, is increasing by
KonstantinChe [14]

Answer:

6216

Step-by-step explanation:

This problem deals with exponential growth.

Final value: F

Present (initial) value: P

Rate of growth: r

Time in years = t

F = P(1 + r)^t

F = 2900(1 + 0.1)^8

F = 6216

Answer: 6216

8 0
3 years ago
Suppose you are starting your own company selling chocolate covered strawberries. You decide to sell the milk chocolate covered
lidiya [134]

Answer:

Step-by-step explanation:

Let x_m and x_w be the production level of milk and white chocolate-covered strawberries respectively. According to the given data, we know the total profit will be

P(x_m,x_w)=$2.25x_m+$2.50x_w

The restrictions can be written as

x_m+x_w \leq  800

x_w\leq x_m/2

x_w\leq 200

All the restrictions can be plotted in the same graph to find the feasible region where all of them are met. The graph is shown in the image below

The optimal solution will be the level of production such that

* All restrictions are met

* The total profit is maximum

The optimal level of production can be found in (at least) one of the vertices of the feasible region. We'll try each one as follows

P(0,0)=0

P(400,200)=$2.25 (400)+$2.50 (200) = $1400

P(600,200)=$2.25 (600)+$2.50 (200) = $1850

P(800,0)=$2.25 (800)+$2.50 (0) = $1800

We must produce 600 milk chocolate-covered strawberries and 200 white chocolate-covered strawberries to have a maximum profit of $1850/month

4 0
3 years ago
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