-15 + w = 6 can anyone help me out

At a zoo, 3 pandas eat a total of 181 1 2pounds of bamboo shoots each day. The male panda eats 3 times as much as the baby. The

S_A_V [24]

Answer:

6037.2 pounds of bamboo shoots does the female panda eat.

Step-by-step explanation:

Total pandas = 3

Total bamboo shoots eaten = 18112 pounds

Let baby panda eats bamboo = x

Male panda eats bamboo= 3x

Female panda eats bamboo = 2x

So, the equation will become

$x+3x+2x=18112$

Now solving the equation to find value of x

$x+3x+2x=18112\\6x=18112\\x=\frac{18112}{6}\\x=3018.6$

The value of x we get : x=3018.6

So, baby panda eats bamboo shoots = 3018.6 pounds

Male panda eats bamboo shoots = 3x = 3(3018.6) = 9055.8 pounds

Female panda eats bamboo shoots = 2x = 2(3018.6)= 6037.2 pounds

So, 6037.2 pounds of bamboo shoots does the female panda eat.

6 0

3 years ago

Solve these linear systems using elimination <3

Dmitry_Shevchenko [17]

Answer:

1.x=3/4y + 2

Step-by-step explanation:

Add 3y to both sides then after youdidnt that divide both sides by 4 Thereyougo the answer.

i have school myself so i only did one.

3 0

3 years ago

A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a day waiting period to purchase

il63 [147K]

Answer:

The 90% confidence interval for the difference between proportions is (-0.260, -0.165).

Step-by-step explanation:

The question is incomplete. The complete question is:

"A survey reported in Time magazine included the question ‘‘Do you favor a federal law requiring a 15 day waiting period to purchase a gun?” Results from a random sample of US citizens showed that 318 of the 520 men who were surveyed supported this proposed law while 379 of the 460 women sampled said ‘‘yes”. Use this information to find a 90% confidence interval for the difference in the two proportions, pm - pw. Subscript pm is the proportion of men who support the proposed law and pw is the proportion of women who support the proposed law. (Round answers to 3 decimal places.)"

We want to calculate the bounds of a 90% confidence interval.

For a 90% CI, the critical value for z is z=1.645.

The sample of men, of size nm=-0.26 has a proportion of pm=0.612.

$p_m=X_m/n_m=318/520=0.612$

The sample 2, of size nw= has a proportion of pw=0.824.

$p_w=X_w/n_w=379/460=0.824$

The difference between proportions is (pm-pw)=-0.212.

$p_d=p_m-p_w=0.612-0.824=-0.212$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_m+X_w}{n_m+n_w}=\dfrac{318+379}{520+460}=\dfrac{697}{980}=0.711$

The estimated standard error of the difference between means is computed using the formula:

$s_{pm-pw}=\sqrt{\dfrac{p(1-p)}{n_m}+\dfrac{p(1-p)}{n_w}}=\sqrt{\dfrac{0.711*0.289}{520}+\dfrac{0.711*0.289}{460}}\\\\\\s_{pm-pw}=\sqrt{0.00039+0.00045}=\sqrt{0.001}=0.029$