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2 years ago

Which number can you add to 15 to get a sum of 0? (-10 -15 15 0 )

Mathematics

1 answer:

kvasek [131]2 years ago

4 0

Answer:

-15

Step-by-step explanation:

15+(-15)=15-15+0

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In the above figure, the radius of curvature is 10 ft and the height of the segment is 2 ft. What's the length of the chord?

erma4kov [3.2K]

A about 12 feet is the lenth of the cord

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3 years ago

HELP PLEASE I'LL GIVE 30 POINTS!!!

jasenka [17]

Answer:

x = 45

Step-by-step explanation:

Straight line has 180 degrees; so if you add all the angles up:

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2 years ago

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The number of students in an school building that have the flu after t days is given by the function

gulaghasi [49]

Step-by-step explanation:

$p(0) = \frac{800}{1 + 49 {e}^{ - 0.2 \times 0} } = \frac{800}{1 + 49} = \frac{800}{50} = 16$

$200 = \frac{800}{1 + 49 {e}^{ - 0.2t} } \\ 200(1 + 49 {e}^{ - 0.2t} ) = 800 \\ 200 + 9800 {e}^{ - 0.2t} = 800 \\ 9800 {e}^{ - 0.2t} = 600 \\ {e}^{ - 0.2t} = \frac{3}{49} \\ ln( {e}^{ - 0.2t} ) = ln( \frac{3}{49} ) \\ - 0.2t = - 2.793 \\ t = 13.96 = 14$

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3 years ago

**15 Points!! What is 2 1/2 x 1 1/2, 5.4 x 2 3/4, and 3.1 x 2/7?

Amiraneli [1.4K]

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6 0

3 years ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$

$\Rightarrow x =(50 \times 14)/57=12.28$ grams

and $y = 14-x= 14-12.28=1.72$ grams.

Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.

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2 years ago